Answer:
For elliptical orbits: seldom
For circular orbits: always
Explanation:
We start by analzying a circular orbit.
For an object moving in circular orbit, the direction of the acceleration (centripetal acceleration) is always perpendicular to the direction of motion of the object.
Since acceleration has the same direction of the force (according to Newton's second law of motion), this means that the direction of the force (the centripetal force) is always perpendicular to the velocity of the object.
So for a circular orbit,
the direction of the velocity of the satellite is always perpendicular to the net force acting upon the satellite.
Now we analyze an elliptical orbit.
An elliptical orbit correponds to a circular orbit "stretched". This means that there are only 4 points along the orbit in which the acceleration (and therefore, the net force) is perpendicular to the direction of motion (and so, to the velocity) of the satellite. These points are the 4 points corresponding to the intersections between the axes of the ellipse and the orbit itself.
Therefore, for an elliptical orbit,
the direction of the velocity of the satellite is seldom perpendicular to the net force acting upon the satellite.
Answer:
Explanation:
1. when both sides of the reactants and the products are equal
like h+oh ⇒ h20
hydrogen has 2 atoms on both sides and oxygen has one on both sides
2. no they are put to balance the equation
3. nope they are treated equally as all the other states
4. no if u are talking about a formula unit like NaCl for example it is aqueous not each element taken on its own if u are talking about just elements then i said before all states are treated equally
5. yup
The coefficient of friction is 0.051
Explanation:
The motion of the skater is a uniformly accelerated motion, therefore we can use the following suvat equation:

where:
v = 0 is the final velocity of the skater (he comes to a stop)
u = 10.0 m/s is his initial velocity
a is the acceleration
is the distance he travels before stopping
Solving for a, we find the acceleration of the skater:

We also know that the net force acting on the skater is the force of friction, therefore we can write (Newton's second law of motion):

where
is the force of friction
m is the mass of the skater
is the coefficient of friction
is the acceleration
is the acceleration of gravity
Solving for
, we find the coefficient of friction:

Learn more about friction:
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Answer:
A red giant or red super giant then a white dwarf
Explanation:
This also depends on what the star classification was to begin with.