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LUCKY_DIMON [66]
3 years ago
6

When the washing machine spins the clothes, _______________

Physics
1 answer:
stira [4]3 years ago
3 0

Answer:

kinetic, light

Explanation:

Washing machine. Electrical energy = Thermal (heat) energy + Kinetic (movement) energy + light energy.

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b) The distance of the red supergiant Betelgeuse is approximately 427 light years. If it were to explode as a supernova, it woul
Nat2105 [25]

Answer:

b) Betelgeuse would be \approx 1.43 \cdot 10^{6} times brighter than Sirius

c) Since Betelgeuse brightness from Earth compared to the Sun is \approx 1.37 \cdot 10^{-5} } the statement saying that it would be like a second Sun is incorrect

Explanation:

The start brightness is related to it luminosity thought the following equation:

B = \displaystyle{\frac{L}{4\pi d^2}} (1)

where B is the brightness, L is the star luminosity and d, the distance from the star to the point where the brightness is calculated (measured). Thus:

b) B_{Betelgeuse} = \displaystyle{\frac{10^{10}L_{Sun}}{4\pi (427\ ly)^2}} and B_{Sirius} = \displaystyle{\frac{26L_{Sun}}{4\pi (26\ ly)^2}} where L_{Sun} is the Sun luminosity (3.9 x 10^{26} W) but we don't need to know this value for solving the problem. ly is light years.

Finding the ratio between the two brightness we get:

\displaystyle{\frac{B_{Betelgeuse}}{B_{Sirius}}=\frac{10^{10}L_{Sun}}{4\pi (427\ ly)^2} \times \frac{4\pi (26\ ly)^2}{26L_{Sun}} \approx 1.43 \cdot 10^{6} }

c) we can do the same as in b) but we need to know the distance from the Sun to the Earth, which is 1.581 \cdot 10^{-5}\ ly. Then

\displaystyle{\frac{B_{Betelgeuse}}{B_{Sun}}=\frac{10^{10}L_{Sun}}{4\pi (427\ ly)^2} \times \frac{4\pi (1.581\cdot 10^{-5}\ ly)^2}{1\ L_{Sun}} \approx 1.37 \cdot 10^{-5} }

Notice that since the star luminosities are given with respect to the Sun luminosity we don't need to use any value a simple states the Sun luminosity as the unit, i.e 1. From this result, it is clear that when Betelgeuse explodes it won't be like having a second Sun, it brightness will be 5 orders of magnitude smaller that our Sun brightness.

4 0
3 years ago
A farmhand pushes a 26-kg bale of hay 3.9 m across the floor of a barn. If she exerts a horizontal force of 88 N on the hay, how
Tamiku [17]

Answer:

W =  343.2 J

Explanation:

Given that,

Mass of bale of hay = 26 kg

Horizontal force exerted = 88 N

Distance moved, d = 3.9 m

Work done, W = Fd

Put all the values,

W = 88 N × 3.9 m

= 343.2 J

So, the work done is 343.2 J.  

7 0
3 years ago
A grocery cart with a mass of 15 kg is pushed at constant speed along an aisle by a force fp = 12 n which acts at an angle of 17
Korolek [52]

<span>Given:

Mass of cart: 15kg</span>

Aisle length = 14m

Angle = 17° below the horizontal

Force fp = 12 N

 

So, the solution would be like this for this specific problem:

 

<span><span>1)    </span>W(by applied force) = F(applied) x s x cosθ <span>
=>W(a) = 12 x 14 x cos17* = 160.66 J </span></span>
<span><span>
2)    </span>By F(net) = F(applied) - F(friction) <span>
=>As v = constant => a = 0 => F(net) = 0 
=>F(applied) = F(friction) 
<span>=>W(friction) = -F(friction) x s
=>W(friction) = -F(applied) x s 
=>W(f) = -12 x 14 x cos17* = -160.56 J </span></span></span>
<span><span>
3)    </span>0, as the displacement is perpendicular to Force </span>
<span><span>
4)    </span>0, as the displacement is perpendicular to Force</span>  
<span>
To add, the force that is applied<span> to an object by a person or another object is called the applied force.</span></span>
8 0
3 years ago
If you're going 80 mph how long does it take to go 80 miles
Elza [17]
1 mile. Is this a joke lol
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4 years ago
University Physics 9.68: Accelerating Compact Disc. A computer disc drive is turned on starting from rest and has constant angul
faust18 [17]

Hey! How are you? My name is Maria, 19 years old. Yesterday broke up with a guy, looking for casual sex.

Write me here and I will give you my phone number - *pofsex.com*

My nickname - Lovely

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