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3 years ago

How is radiation used to treat cancer?

2 answers:

ozzi3 years ago

8 0

Radiation therapy kills cancer cells or slows their growth by damaging their DNA. Radiation therapy (also called radiotherapy) is a cancer treatment that uses high doses of radiation to kill cancer cells and shrink tumors.

Luda [366]3 years ago

3 0

Radiation kills the cancer cells or slows rhere growth by damaging DNA

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Lin suffers from pain in her right wrist. Several doctors check her wrist regularly over a period of time. Doctors' notes and

FromTheMoon [43]

Answer:

Explanation:

They looked at her hand and made a formal conclusion from that

4 0

3 years ago

A ray of monochromatic light ( f = 5.09 × 10^14 Hz) passes from air into Lucite at an angle

harina [27]

Let us consider the air with the index 1 and the lucite with index 2. Using the Snell's Secound Law, we have:

$\frac{sen\O_{2}}{sen\O_{1}} = \frac{n_{2}}{n_{1}} \\ sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}}$

Entering the unknowns, remembering that the air refrective index is 1 and the lucite refrective index is 1.5, comes:

$sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}} \\ sen\O_{2}= \frac{1.5* \frac{1}{2} }{1} \\ sen\O_{2}=0.75$

Using the arcsin properties, we get:

$sen\O_{2}=0.75 \\ arcsin(0.75)=\O_{2} \\ \boxed {\O_{2}=48.59^o}$

Obs: Approximate results, and the drawing is attached

If you notice any mistake in my english, let me know, because i am not native.

6 0

3 years ago

Fast breeder reactor technology definition

mixas84 [53]

The definition is a nuclear reactor that generates more fissile material than it consumes.

5 0

3 years ago

An Object, Start from rest w Confront Aiceleration 8m/s2 along a

shutvik [7]

Answer:

A) v = 40 m / s, B) v_average = 20 m / s

Explanation:

For this exercise we will use the kinematics relations

A) the final velocity for t = 5 s and since the body starts from rest its initial velocity is zero

v = vo + a t

v = 0 + 8 5

v = 40 m / s

B) the average velocity can be found with the relation

v_average = vf + vo / 2

v-average = 0+ 40/2

v_average = 20 m / s

6 0

3 years ago

Moving by short leaps on one foot at a time.

Evgen [1.6K]

The answer is:

Hopping.

Explanation:

Hopping is done by taking off on one foot and landing back on that same foot. Hopping is done in shorter intervals, meaning you usually don't travel large distances through a single hop. Hopping is categorized as short leaps for its small distance covered singularly, and each hop is done only on one foot.

<em>(Think about if one of your feet/legs is injured or asleep. If you wanted to go from say the living room to the kitchen, but didn't wish to move that leg or foot, you would likely hop on one foot to get to the destination.)</em>

6 0

3 years ago