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3 years ago

The difference between three times a number and two

Mathematics

1 answer:

ziro4ka [17]3 years ago

4 0

Answer:

3x - 2

Step-by-step explanation:

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The circumference of a circle is 12π cm. Find its diameter, in centimeters.

inessss [21]

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3 years ago

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Arrange the following numbers in order from greatest to least 7,361; 7,136; 7,613

d1i1m1o1n [39]

7,613 ,7,361,7,136

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3 0

3 years ago

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Calcula el lado y el área de un poligono regular 12 lados sabiendo que su radio es de 7,727dmy su apotema de 7,464

Vika [28.1K]

Answer:

$L=3.999 \: dm$

$A=183.4581\:dm^{2}$

Step-by-step explanation:

La relación del apotema y el lado de un dodecágono regular está dada por la siguiente ecuación:

$a_{p}=L\frac{2+\sqrt{3}}{2}$

Sabiendo que la apotema es 7.464 el lado sera:

$L=\frac{2*a_{p}}{2+\sqrt{3}}$

$L=\frac{2*7.464}{2+\sqrt{3}}$

$L=3.999 \: dm$

Por otro lado el area de un dodecágono regular esta dada por:

$A=6a_{p}L$

$A=6*7.646*3.999$

$A=183.4581\:dm^{2}$

Espero te haya sido de ayuda!

7 0

3 years ago

Csn someone please help?

sdas [7]

Answer:

A=-2 B=17

Step-by-step explanation:

8 0

3 years ago

Air pressure may be represented as a function of height (in meters) above the

denis-greek [22]

Answer: OPTION C.

Step-by-step explanation:

<h3> The complete exercise is: "Air pressure may be represented as a function of height (in meters) above the surface of the Earth, as shown below:</h3><h3> $P(h) =P_0e^{-0.00012h}$ </h3><h3> In this function $P_o$ is the air pressure at the surface of the earth, and $h$ is the height above the surface of the Earth, measured in meters. At what height will the air pressure equal 50% of the air pressure at the surface of the Earth"</h3><h3></h3>

Given the following function:

$P(h) =P_0e^{-0.00012h}$

In order to calculate at what height the air pressure will be equal 50% of the air pressure at the surface of the Earth, you can follow these steps:

1. You need to substitute $P(h)=0.5P_o$ into the function:

$0.5P_o=P_0e^{-0.00012h}$

2. Finally, you must solve for $h$ .

Remember the following property of logarithms:

$ln(b)^a=a*ln(b)\\\\ln(e)=1$

Then, you get this result:

$0.5P_o=\frac{P_o}{e^{0.00012h}}\\\\(0.5P_o)(e^{0.00012h})=P_o\\\\e^{0.00012h}=\frac{P_o}{0.5P_o}\\\\ln(e)^{0.00012h}=ln(2)\\\\0.00012h*1=ln(2)\\\\h=\frac{ln(2)}{0.00012}\\\\h=5576.2$

7 0

4 years ago