Let's call the two numbers x and y. We can write a system of equations to describe the situation:
5x = 8y
x - y = 150
Let's solve the first equation for x:
x = 8y/5
Now we can use substitution to solve the system by plugging 8y/5 in for x in the second equation:
(8y/5) - y = 150
Simplify:
3y/5 = 150
3y = 750
y = 250
If y = 250, then x is:
x = 8(250)/5 = 400
The answer is 250 and 400.
Answer:
The experimental factor that is manipulated; the variable whose effect is being studied is called <u>independent variable.</u>
Step-by-step explanation:
Consider the provided information.
In an experiment, the two principal variables are the independent and dependent variable.
An independent variable is the variable that is altered or controlled to test the effects on the dependent variable in a scientific experiment.
The variable which is tested and measured in a scientific experiment is a dependent variable.
From the above definition: The experimental factor that changed or controlled in a scientific experiment is called independent variable.
Therefore, the complete statement is: The experimental factor that is manipulated; the variable whose effect is being studied is called <u>independent variable.</u>
-2x/5-2=18
-2x/5-2+2=18+2
-2x/5=20
-2x/5x5=20x5
-2x=100
-2x/-2=100/-2
x=-50
Answer:43.98cm
Step-by-step explanation:
Answer:
Step-by-step explanation:
9) PQR Is an isosceles triangle
=> ∠PRQ = (180° - x)/2
PRS is an isosceles right triangle
=> ∠PRS = 45°
Have: ∠PRS + ∠PRQ = 115°
=> 
=> 180 - x = (115 - 45).2 = 140
<=> x = 180 - 140 = 40
10) ABD is an isosceles right triangle => ∠ABD = 45°
BCD is an equilateral triangle => ∠CBD = 60°
have: x = ∠ABD + ∠CBD = 45° + 60° = 105°
11) have: x = y (2)
PQT is an isosceles triangle => ∠PQT = 180 - 70.2 = 40
QTS is an isosceles triangle => ∠TQS = 180 -2x
QRS is an isosceles triangle => ∠RSQ = y
have: 40 + 180 - 2x + y = 180 => 2x - y = 40 (1)
(1)(2) => 
=> x + y = 80
12) EFJ Is an equilateral triangle => ∠FJE = 60
∠FJE is the outer angle of the triangle FHJ but FHJ is an isosceles triangle
=> 60 = 2.∠JHF => ∠JHF = 30°
∠JHF is the outer angle of the triangle FHG
=> 30° = 2x
<=> x = 15°
