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Sholpan [36]
3 years ago
8

Calculate the force needed to accelerate a baseball with a mass of 0.45

Physics
1 answer:
RideAnS [48]3 years ago
8 0
  • Mass=0.45kg
  • Acceleration=175m/s^2

\\ \bull\tt\dashrightarrow F=ma

\\ \bull\tt\dashrightarrow F=0.45(175)

\\ \bull\tt\dashrightarrow F=78.75N

\\ \bull\tt\dashrightarrow F=78.8N

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A square sheet of rubber has sided that are 20 cm long. If you stretch one side so that it is twice as long. What is the new are
Anika [276]

Answer:ignore this it was wrong

Explanation:

3 0
4 years ago
a car accelerates uniformly from rest to a speed of 65 km/h (18 m/s) in 12s. Find the distance the car travels during this time?
Vinil7 [7]

The car's speed was zero at the beginning of the 12 seconds,
and 18 m/s at the end of it.  Since the acceleration was 'uniform'
during that time, the car's average speed was (1/2)(0 + 18) = 9 m/s.

12 seconds at an average speed of 9 m/s  ==>  (12 x 9) = 108 meters .

==========================================

That's the way I like to brain it out.  If you prefer to use the formula,
the first problem you run into is:  You need to remember the formula !

The formula is        D = 1/2 a T²

                   Distance = (1/2 acceleration) x (time in seconds)²

             Acceleration = (change in speed) / (time for the change)
                                  =        (18 m/s)            /        (12 sec)
                                  =                      1.5 m/s² .

                  Distance  =  (1/2 x 1.5 m/s²) x (12 sec)²
                                  =       (0.75 m/s²)  x  (144 sec²)  =  108 meters .

5 0
4 years ago
Laura sees a horse pulling a buggy. She wonders how it can accelerate if the action of the horse pulling the cart would cause an
cricket20 [7]

Answer:

The net forces exerted on the horse and cart are not the same, so they are not balanced forces.

Explanation:

Using newton laws,

ΣF = ma

The two forces acting on the body is the forward force by the horse and the frictional force opposing the forward force

F-Fr= ma

Therefore,

F=ma+Fr

So the forward (by horse) is more than the opposite reaction (by cart).

The only time the forward force and the opposite reaction are the same is when a=0, I.e, the body is not moving at all or the body is moving at constant velocity.

3 0
3 years ago
Read 2 more answers
A solution containing 10.0 g of an unknown liquid and 90.0 g water has a freezing point of -3.33 °C. Given Kf = 1.86 °C/m for wa
Fantom [35]

Answer:

62.06 g/mol

Explanation:

We are given that a solution containing 10 g of an unknown liquid and 90 g

Given mass of solute =W_B=10 g

Given mass of solvent=W_A=90 g

k_f=1.86^{\circ}C/m

Freezing point of solution =-3.33^{\circ}C

Freezing point of solvent =0^{\circ}C

Change in freezing point =Depression in freezing point

=Freezing point of solvent - freezing point of solution=0+3.33=3.33^{\circ}

\Delta T_f=\frac{W_B\times K_f\times 1000}{W_A\times M_B}

M_B=\frac{10\times 1.86\times 1000}{3.33\times 90}

M_B=62.06 g/mol

Hence, molar mass of unknown liquid is 62.06g/mol.

6 0
3 years ago
Read 2 more answers
How to protect the ozone layer?
Nady [450]

Answer:

\huge{\purple{\underline{\underline{\bf{\pink{Answer}}}}}}

  1. we have to protect ozone layer because it is like blanket for earth . It protects the earth form uv rays that are coming from the sun

we have to take some preventive. measures like

  • Use ecofriendly things that Doesnot contain (cfc) . It is the major reason for ozone Deplition

Effects of uv rays

  • Uv rays are very harmful . If it directly comes in contact with human it cause skin cancer , eyes irritation etc.

Hope it helps.

3 0
3 years ago
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