Question

A common carnival ride, called a gravitron, is a large r = 11 m cylinder in which people stand against the outer wall. the cylinder spins so that the riders move with a linear speed v. At a certain point the floor of the cylinder lowers and the people are surprised they don't slide down. The friction between the wall and their clothes is μs = 0.51.

Answer 1

Answer:

The minimum speed is 14.53 m/s.

Explanation:

Given that,

r = 11 m

Friction coefficient = 0.51

Suppose we need to find the minimum speed, that the cylinder must make a person move at to ensure they will stick to the wall

When frictional force becomes equal to or greater than the weight of person

Then, he sticks to the wall

We need to calculate the minimum speed

Using formula for speed

$f_{s}=\mu N\geq mg$

Where, $N =\dfrac{mv^2}{r}$

$\mu\times\dfrac{mv^2}{r}\gep mg$

$v^2\geq\dfrac{gr}{\mu}$

Put the value into the formula

$v=\sqrt{\dfrac{9.8\times11}{0.51}}$

$v=14.53\ m/s$

Hence, The minimum speed is 14.53 m/s.