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Zanzabum
3 years ago
10

III. Classify each substance as solute or solvent. 1. buko juice 2. vinegar 3. flour 4. coffee powder 5. salt​

Physics
1 answer:
frutty [35]3 years ago
8 0

<em><u>ANSWER</u></em>

my answer is in the photo above

<u>EXPLANATION</u>

A solvent is a substance in which a solute dissolves and solvents are in most cases liquids while a solute is a substance that dissolves in a solute and in their especially solid in nature

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carbon dioxide

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A cylinder is given a push and then rolls up an inclined plane. If the origin is the starting point, sketch the position, veloci
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3 years ago
The velocity of a particle traveling in a straight line is given by v = (6t - 3t²) m/s, where t is in seconds. If s = 0 when t =
qaws [65]

Answer

given,

v = (6 t - 3 t²) m/s

we know,

v = \dfrac{dx}{dt}

a = \dfrac{dv}{dt}

position of the particle

dx = v dt

integrating both side

\int dx = (6t - 3 t^2)\int dt

 x = 3 t² - t³

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 x = 3  x 3² - 3³

 x = 0 m

now, particle’s deceleration

a = \dfrac{dv}{dt}

a = \dfrac{d}{dt}(6t - 3 t^2)

  a = 6 - 6 t

at t= 3 s

    a = 6 - 6 x 3

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distance traveled by the particle

  x = 3 t² - t³

at t = 0 x = 0

   t = 1 s   , x = 3 (1)² - 1³ = 2 m

   t = 2 s  ,  x = 3(2)² - 2³ = 4 m

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D = distance in 0-1 s + distance in 1 -2 s + distance in 2 -3 s

D = 2 + 4 + 2 = 8 m

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v_{avg} = \dfrac{distance}{time}

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8 0
3 years ago
The radius of curvature of a highway exit is r = 93.5 m. The surface of the exit road is horizontal, not banked. (See figure.)
trapecia [35]

Static friction keeps the car from skidding off the road and points toward the center of the curve. By Newton's second law, the car experiences

• net vertical force

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It follows that

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Solve for v :

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8 0
3 years ago
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