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viktelen [127]
3 years ago
14

Reposting the repost because it got deleted TvT

Physics
1 answer:
kakasveta [241]3 years ago
5 0

Answer:

Because water mixes with the dirt when it rains to make that mud when the mud is left in the sun, the sun <em>Evaporates</em><em> </em>that water, and eventualy it will turn into sand.

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Boxes A and B are in contact on a horizontal, frictionless surface. Box A has mass 20.0 kg and box B has mass 5.0 kg. A horizont
bazaltina [42]

Answer:

80 N

Explanation:

For A + B: the net force is 100 N = (mA + mB)*a

a = 100/(20 + 5) = 100/25 = 4 m/s²

For A, the net force = mA * a = 20 * 4 = 80 N

3 0
2 years ago
One advantage of a fever is that it can slow down the
AlexFokin [52]
One advantage of a fever is that it can slow down the growth of pathogens by denaturing their proteins.
8 0
4 years ago
Two kilograms of air is contained in a rigid wellinsulated tank with a volume of 0.6 m3 . The tank is fitted with a paddle wheel
wolverine [178]

Answer:

0.3\ \text{m}^3/\text{kg}

36\ \text{kJ}

18\ \text{kJ/kg}

Explanation:

V = Volume of air = 0.6\ \text{m}^3

P = Power = 10 W

t = Time = 1 hour

m = Mass of air = 2 kg

Specific volume is given by

v=\dfrac{V}{m}\\\Rightarrow v=\dfrac{0.6}{2}\\\Rightarrow v=0.3\ \text{m}^3/\text{kg}

The specific volume at the final state is 0.3\ \text{m}^3/\text{kg}

Work done is given by

W=Pt\\\Rightarrow W=10\times 60\times 60\\\Rightarrow W=36000\ \text{J}=36\ \text{kJ}

The energy transfer by work, is 36\ \text{kJ}

Change in specific internal energy is given by

\Delta u=\dfrac{Q}{m}+\dfrac{W}{m}\\\Rightarrow \Delta u=0+\dfrac{36}{2}\\\Rightarrow \Delta u=18\ \text{kJ/kg}

The change in specific internal energy of the air is 18\ \text{kJ/kg}

8 0
3 years ago
While investigating the relationship between voltage, current, and resistance, students connected different batteries to differe
GuDViN [60]

Produced the model is the resistance of the circuits decreased as a battery voltage increased (option-B).

<h3>What connection does there exist between voltage and current, current and resistance, and voltage and resistance?</h3>

Ohm's Law describes how current, voltage, and resistance are related to one another. According to this, as long as the temperature doesn't change, the current flowing through a circuit is directly proportional to the applied voltage and inversely proportional to the resistance of the circuit.

The more work a certain quantity of electrons can accomplish at a given voltage. The quantity of electrons that are presently moving through any one point in a circuit at any particular time is known as the current. At the same voltage, a larger current can perform more work. Current times voltage equals power.

To know more about current visit:

brainly.com/question/13076734

#SPJ13

4 0
1 year ago
The lens of a telescope has a diameter of 25 cm. You are using it to look at two stars that are 2 × 1017 m away from you and 6 ×
vagabundo [1.1K]

Answer:

a)It is NOT possible using this telescope, to see the two stars as separate stars

b)d_{min} =28.466m

Explanation:

From the question we are told that:  

Diameter of lens,d = 25 cm \approx 0.25 m

Distance from both star D_f= 2*10^{17} m

Distance between both stars D_b= 6*10^9 m

Wavelength of light \lambda =700 nm \approx 700*10^-9 m

Generally the equation for angle subtended by the two stars at the lens  is mathematically given by

 \theta=\frac{D_f}{D_b}

 \theta=\frac{6*10^9}{2*10^{17}}

 \theta=3.0*10^{-8} rad

Generally the equation for minimum angular separation of two object is mathematically given by

\theta_{min} = 1.22*\lambda/d  

\theta_{min}= \frac{1.22*700*10^-9}{0.25}  

\theta_{min}= 3.416*10^-^6 rad

Therefore

 \theta < \theta_{min}

3.0*10^{-8} rad<  3.416*10^-^6 rad

It is NOT possible using this telescope, to see the two stars as separate stars

b)

Generally the equation for minimum diameter of the lens is mathematically given by

  d_{min} =\frac{ 1.22*\lambda}{\theta}

  d_{min} =\frac{ 1.22*700*10^{-9}}{3*10^{-8}}

  d_{min} =28.466m

3 0
3 years ago
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