Answer:
191.36 N/m
Explanation:
From the question,
The Potential Energy of the safe = Energy of the spring when it was compressed.
mgh = 1/2ke²............... Equation 1
Where m = mass of the safe, g = acceleration due to gravity, h = height of the save above the heavy duty spring , k = spring constant, e = compression
Making k the subject of the equation,
k =2mgh/e²................ Equation 2
Given: m = 1100 kg, h = 2.4 mm = 0.0024 m, e = 0.52 m
Constant: g = 9.8 m/s²
Substitute into equation 2
k = 2(1100)(9.8)(0.0024)/0.52²
k = 51.744/0.2704
k = 191.36 N/m
Hence the spring constant of the heavy-duty spring = 191.36 N/m
Answer:
R= 20 ohm
Explanation:
Given that
Current ,I = 6 A
Voltage difference ,ΔV = 120 V
Lets take resistance of the stem iron = R
We know that ,the relationship between current ,voltage difference and resistance is given as
ΔV = I R
Now by putting the values in the above equation we get
R= 20 ohm
Therefore the resistance of the steam will be 20 ohm.
A lab cart is loaded with different masses and moved at various constant velocities? the anser should be
1.0m/s → 4kg
I think its Coulomb's law<span>
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