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3 years ago

What are some factors that might stop a population's exponential growth

2 answers:

7 0

Lack of food, lack of shelter, disease, war, genocide, putting a limit to the amount of kids one may have, or how many can exist in a single generation.

lyudmila [28]3 years ago

3 0

So first of all, you might run out of food, which means that there wont be enough to sustain too many animals/people.
Or, you could simply run out of the space to have any more offspring.
One final one is the introduction of a new predator, which would eat the population, making the growth unpredictable.

Hope this helped!!!! :D

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A young diver is practicing his skills before an important team competition. Use the diagram below in order to analyze the energ

nika2105 [10]

h=10m-5m=5m
m=90Kg
g=9.8m/s^2

$\\ \sf\longmapsto GPE=mgh$

$\\ \sf\longmapsto GPE=90(5)(9.8)$

$\\ \sf\longmapsto G PE=4410J$

Now

It's converted to kinetic energy while reaching ground.

$\\ \sf\longmapsto K.E=4410$

$\\ \sf\longmapsto \dfrac{1}{2}mv^2=4410$

$\\ \sf\longmapsto 90v^2=8820$

$\\ \sf\longmapsto v^2=98$

$\\ \sf\longmapsto v=9.9m/s$

Done

7 0

2 years ago

Read 2 more answers

Don't you ever feel like thursday is like the number 7?

Ostrovityanka [42]

Bruh whatttt sjskskskskdk

5 0

3 years ago

Newtons second law states that Force=Mass × Acceleration.The acceleration of gravity in 9.8 m/s.How much force is gravity exerti

Naddika [18.5K]

.98 Newton’s because you convert 100 g to kg which is .1 kg them you multiply.1 kg by 9.8 and get .98 and the units of the force are in Newton’s

5 0

3 years ago

A 1.11 kg piece of aluminum at 78.3 c is put into a glass with 0.210 kg of water at 15.0

ValentinkaMS [17]

M = mass of aluminium = 1.11 kg

$c_{a}$ = specific heat of aluminium = 900

$T_{ai}$ = initial temperature of aluminium = 78.3 c

m = mass of water = 0.210 kg

$c_{w}$ = specific heat of water = 4186

$T_{wi}$ = initial temperature of water = 15 c

T = final equilibrium temperature = ?

using conservation of heat

Heat lost by aluminium = heat gained by water

M $c_{a}$ ( $T_{ai}$ - T) = m $c_{w}$ (T - $T_{wi}$ )

(1.11) (900) (78.3 - T) = (0.210) (4186) (T - 15)

T = 48.7 c

7 0

3 years ago

on a very muddy football field, a 120 kg linebacker tackles an 75 kg halfback. immediately before the collision, the linebacker

DIA [1.3K]

Momentum
- a vector quantity; has both magnitude and direction
- has the same direction as object's velocity
- can be represented by components x & y.

Find linebacker momentum given m₁ = 120kg, v₁ = 8.6 m/s north
P₁ = m₁v₁
P₁ = (120)(8.6)
[ P₁ = 1032 kg·m/s ] = y-component, linebacker momentum

Find halfback momentum given m₂ = 75kg, v₂ = 7.4 m/s east
P₂ = m₂v₂
P₂ = (75)(7.4)
[ P₂ = 555 kg·m/s ] = x-component, halfback momentum

Find total momentum using x and y components.
P = √(P₁)² + (P₂)²
P = √(1032)² + (555)²
[[ P = 1171.77 kg·m/s ]] = magnitude

!! Finally, to find the magnitude of velocity, take the divide magnitude of momentum by the total mass of the players.
P = mv
P = (m₁ + m₂)v
1171.77 = (120 + 75)v [solve for v]
v = 1171.77/195
v = 6.0091 ≈ 6.0 m/s

If asked to find direction, take inverse tan of x and y components.
tanθ = (y/x)
θ = tan⁻¹(1032/555)
[ θ = 61.73° north of east. ]

The magnitude of the velocity at which the two players move together immediately after the collision is approximately 6.0 m/s.

6 0

3 years ago