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Lilit [14]
3 years ago
9

Standard solar panels transform 3,600,000 J of input light energy into 720,000 J of useful electrical energy. The new solar pane

ls that mimic butterfly wings are thought to have double the energy efficiency.
Calculate the energy efficiency of the new solar panel improved through biomimicry.
Physics
1 answer:
dangina [55]3 years ago
7 0

Answer:

5

Explanation:

we divide 3600000J by 720,000J

and after that the answer will be 5

3600,000J

---------------

720,000J

=5answer

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To describe velocity you need to know _______ and _________
Crazy boy [7]
To get the velocity you need to know the displacement and the time.

I hope that helps!
5 0
3 years ago
Read 2 more answers
1. What is the kinetic energy of a ball with a mass of 5 kg rolling<br> at 10 m/s?
Kazeer [188]

KE=1/2mv^2

KE= 0.5×5kg×10m/s^2

KE=250J

5 0
4 years ago
A model rocket rises with constant acceleration to a height of 4.2 m, at which point its speed is 27.0 m/s. How much time does i
geniusboy [140]

Answers:

a) t=0.311 s

b) a=86.847 m/s^{2}

c) y=1.736 m

d) V=17.369 m/s

Explanation:

For this situation we will use the following equations:

y=y_{o}+V_{o}t+\frac{1}{2}at^{2} (1)  

V=V_{o} + at (2)  

Where:  

y is the <u>height of the model rocket at a given time</u>

y_{o}=0 is the i<u>nitial height </u>of the model rocket

V_{o}=0 is the<u> initial velocity</u> of the model rocket since it started from rest

V is the <u>velocity of the rocket at a given height and time</u>

t is the <u>time</u> it takes to the model rocket to reach a certain height

a is the <u>constant acceleration</u> due gravity and the rocket's thrust

<h2>a) Time it takes for the rocket to reach the height=4.2 m</h2>

The average velocity of a body moving at a constant acceleration is:

V=\frac{V_{1}+V_{2}}{2} (3)

For this rocket is:

V=\frac{27 m/s}{2}=13.5 m/s (4)

Time is determined by:

t=\frac{y}{V} (5)

t=\frac{4.2 m}{13.5 m/s} (6)

Hence:

t=0.311 s (7)

<h2>b) Magnitude of the rocket's acceleration</h2>

Using equation (1), with initial height and velocity equal to zero:

y=\frac{1}{2}at^{2} (8)  

We will use y=4.2 m :

4.2 m=\frac{1}{2}a(0.311)^{2} (9)  

Finding a:

a=86.847 m/s^{2} (10)  

<h2>c) Height of the rocket 0.20 s after launch</h2>

Using again y=\frac{1}{2}at^{2} but for t=0.2 s:

y=\frac{1}{2}(86.847 m/s^{2})(0.2 s)^{2} (11)

y=1.736 m (12)

<h2>d) Speed of the rocket 0.20 s after launch</h2>

We will use equation (2) remembering the rocket startted from rest:

V= at (13)  

V= (86.847 m/s^{2})(0.2 s) (14)  

Finally:

V=17.369 m/s (15)  

5 0
3 years ago
Physical
zysi [14]

Answer: 2.5

Explanation:

4 0
3 years ago
It takes a car 1.75 h to go from mile marker 115 what's the average speed of the car?
emmainna [20.7K]
The average speed of the car is

               (the mile marker he passes at the end of the 1.75 h) minus 115
divided by
               (1.75 hours) .

The unit is 'miles per hour'.
6 0
3 years ago
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