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gtnhenbr [62]
3 years ago
14

A man runs 800m due north in 110 seconds followed by 400m due suoth in 90 seconds calculate his average speed and his average ve

locity​
Physics
1 answer:
andrey2020 [161]3 years ago
6 0

Answer:

Average speed is  6m/s

Average velocity is 5.859m/s

Explanation:

Average speed, s = d/t

d is distant

t is time

speed north is 800m and 110s

speed due south is 400m and 90s  

Average speed = (800+400) / (110+90)

                          = 1200/200

                          =6m/s

Average velocity V = (v + u)/2

v = final velocity

u = initial velocity

V = (7.273 + 4.444)/2 = 11.717/2

V = 5.859m/s

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3 years ago
A biker first accelerates from 0.0 m/s to 6.0 m/s in 6 s, then continues at this speed for 5 s. What is the total distance trave
Svetradugi [14.3K]

Answer:

48m

Explanation:

Given the following data;

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Time, t = 6 secs

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Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

Substituting into the equation;

a = \frac{6 - 0}{6}

a = \frac{6}{6}

Acceleration, a = 1m/s²

<u>To find the distance covered in the first phase;</u>

<em>Solving for distance, we would use the second equation of motion;</em>

S = ut + \frac {1}{2}at^{2}

<em>Substituting the values into the equation;</em>

S = 0(6) + \frac {1}{2}*1*(6)^{2}

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<u>For the second phase, time T2 = 5 secs;</u>

<em>Mathematically, speed is given by the equation;</em>

Speed = \frac{distance}{time}

<em>Making distance the subject of formula, we have;</em>

Distance, S = speed * time

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3 years ago
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yaroslaw [1]

Answer:

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4 years ago
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Answer:

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