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1 answer:
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Answer:
841.5 Hz
Explanation:
Given
y = 50 cm = 0.5 m
d = 5.00 m
L = 12.0 m away from the wall
v = speed of sound = 343 m/s
The image of the scenario is presented in the attached image.
When destructive interference is being experienced from 50 cm (0.5 m) parallel to the wall, the path difference between the distance of the two speakers from the observer is equal to half of the wavelength of the wave.
Let the distance from speaker one to the observer's new position be d₁
And the distance from the speaker two to the observer's new position be d₂
(λ/2) = |d₁ - d₂|
d₁ = √(12² + 3²) = 12.3693 m
d₂ = √(12² + 2²) = 12.1655 m
|d₁ - d₂| = 0.2038 m
(λ/2) = |d₁ - d₂| = 0.2038
λ = 0.4076 m
For waves, the velocity (v), frequency (f) and wavelength (λ) are related thus
v = fλ
f = (v/λ) = (343/0.4076) = 841.5 Hz
Hope this Helps!!!
Answer:
The number of O₂ molecules that are left in the cylinder is 1.70x10²⁴.
Explanation:
The number of oxygen molecules can be found using the Ideal Gas law:
Where:
P: is the pressure = 100 psi
V: is the volume = 10 L
n: is the number of moles =?
T: is the temperature = 20 °C = 293 K
R: is the gas constant = 0.082 L*atm/(K*mol)
Hence, the number of moles is:
Now, the number of molecules can be found with Avogadro's number:
Therefore, the number of O₂ molecules that are left in the cylinder is 1.70x10²⁴.
I hope it helps you!