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erastovalidia [21]
3 years ago
11

Please help me I will give brainliest to you

Physics
1 answer:
Ainat [17]3 years ago
3 0

Answer:

a) Plant cell

Hope it helps.

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How much soil is in a 5 cm to 9 cm deep hole?
vlabodo [156]
There is no soil in a hole

;)
6 0
3 years ago
A large box slides across a frictionless surface with a velocity of 12 m/s and a mass of 4
denpristay [2]
Answer= 8m/s

Because total Momentum before= total momentum after

Momentum before (p=mu)
p=(4)(12)= 48
p=2(0)=0
So total momentum before=48

Momentum after (p=mu)
Masses combined —2+4=6kg
p=6u


Mb=Ma
48=6u
u=8m/s
3 0
2 years ago
What is the power of a diverging lens of focal length 0.4 m
romanna [79]

Answer:

-2.5 is the answer to your question

4 0
3 years ago
Write an expression for the potential energy UD of a particle when it is at a distance D from the force center, in terms of B an
nadezda [96]

Answer:

E+mc+UD-3

Explanation:

7 0
3 years ago
A 65.0-kg runner has a speed of 5.20 m/s at one instant dur- ing a long-distance event. (a) What is the runner’s kinetic energy
vladimir2022 [97]

Answer:

a)KE=878.8 J

b)W=2636.4 J      

Explanation:

Given that

mass ,m = 65 kg

Initial speed ,u = 5.2 m/s

a)

We know that kinetic energy KE is given as follows

KE=\dfrac{1}{2}mu^2

m=mass

u=velocity

Now by putting the values in the above equation we get

KE=\dfrac{1}{2}\times 65\times 5.2^2\ J

KE=878.8 J

b)

We know that

Work done by all forces = Change in the kinetic energy

The final velocity , v= 2 u = 2 x 5.2 m/s

v= 10.4 m/s

W=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2

Now by putting the values in the above equation we get

W=\dfrac{1}{2}\times 65\times 10.4^2-\dfrac{1}{2}\times 65\times 5.2^2\ J

W=2636.4 J

a)KE=878.8 J

b)W=2636.4 J

8 0
3 years ago
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