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3 years ago

Please help me I will give brainliest to you

Physics

1 answer:

Ainat [17]3 years ago

3 0

Answer:

a) Plant cell

Hope it helps.

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Particles at the very outer edge of Saturn’s A Ring are in a 7:6 orbital resonance with the moon Janus. If the orbital period of

vivado [14]

Answer:

14 hours 18 minutes.

Explanation:

ratio of number of orbits, so it completes 7 orbits in the time Janus does 6.

(16*60+41)*6/7=858 minutes or 14 hours 18 minutes

3 0

4 years ago

Pls can anyone solve this

gayaneshka [121]

Answer:

3 pls give me brainliest

Explanation:

8 0

3 years ago

Who represents the worst of the iron age in his attempt to feed jupiter once living flesh?

wolverine [178]

Lycaon represents the worst of the iron age in his attempt to feed jupiter once living flesh.

The iron Age is the final epoch of the three-age division of the prehistory and protohistory of humanity.

It was preceded by the Stone Age, and the Bronze Age.

Who is lycaon?

In Greek mythology, Lycaon was a king of Arcadia who, in the most popular version of the myth, tested Zeus' omniscience by serving him the roasted flesh of Lycaon's own son Nyctimus, in order to see whether Zeus was truly all-knowing.

Thus, Lycaon represents the worst of the iron age in his attempt to feed jupiter once living flesh.

Learn more about lycaon here: brainly.com/question/18610700

#SPJ1

4 0

2 years ago

Water is drawn from a well in a bucket tied to the end of a rope whose other end wraps around a solid cylinder of mass 50 kg and

sleet_krkn [62]

Answer:

$\alpha=78.4\ rad.s^{-2}$

Explanation:

Given:

mass of solid cylinder, $m=50\ kg$

diameter of cylinder, $d=0.25\ m$

mass of bucket of water, $m_w=20\ kg$

<em>When the bucket is released to fall in the well, it fall under the acceleration due to gravity.</em>

We have formula for angular acceleration as:

$\alpha=\frac{g}{r}$

where:

g = acceleration due to gravity

r = radius of the cylinder

$\aplha=\frac{9.8}{0.125}$

$\alpha=78.4\ rad.s^{-2}$

4 0

3 years ago

A copper wire 1.0 meter long and with a mass of .0014 kilograms per meter vibrates in two segments when under a tension of 27 Ne

Furkat [3]

Answer:

the frequency of this mode of vibration is 138.87 Hz

Explanation:

Given;

length of the copper wire, L = 1 m

mass per unit length of the copper wire, μ = 0.0014 kg/m

tension on the wire, T = 27 N

number of segments, n = 2

The frequency of this mode of vibration is calculated as;

$F_n = \frac{n}{2L} \sqrt{\frac{T}{\mu} } \\\\F_2 = \frac{2}{2\times 1} \sqrt{\frac{27}{0.0014} }\\\\F_2 = 138.87 \ Hz$

Therefore, the frequency of this mode of vibration is 138.87 Hz

7 0

3 years ago