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Novay_Z [31]
3 years ago
8

Which is one physical property that all stars have

Physics
1 answer:
UNO [17]3 years ago
6 0

Answer:

Star characteristics consider physical characteristics such as stellar mass, size, surface temperature, and luminosity .

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A 2.00-kg block is pushed against a spring with negligible mass and force constant k = 400 N/m, compressing it 0.220 m. When the
marin [14]

Answer:

0.82052 m

Explanation:

potential energy of spring = kinetic energy

=> 0.5kx^2 = 0.5mv^2

=> v=\sqrt{\frac{kx^2}{m} }

v=\sqrt{\frac{400\times 0.220^2}{2} }

v= 3.11127 m/s

angle = 37°

thus height = distance×sin(37) = D×0.60182

Also,

m×g×h = 0.5×m×v^2

=> 2×9.8×D×0.60182 = 0.5×2×3.11127×3.11127

=> D = 0.82052 m

4 0
3 years ago
Samantha wants to determine the force she feels in her car as she's going around a corner. What would be some of the assumptions
dalvyx [7]

To determine the Force it is necessary that Samantha starts from the consideration of the dynamic balance between the forces acting on the car. For this, the centripetal force must be equal to the friction force (otherwise the car would lose contact with the ground), the expression of these two forces would be

F_f = F_c

\mu_k mg = \frac{mv^2}{r}

Here,

\mu_k = Coefficient of kinematic friction

m = mass

g = Acceleration due to gravity

v = Velocity

r = Radius

From this relationship then she should assume the following

1) The car travels at a constant speed

2) There is indeed that frictional force between the car and the road

3) There is no loss of mass during displacement

4) The centripetal force must be equal to the frictional force so that the car does not lose contact or slip

5) The radius must be constant

7 0
3 years ago
Which bulbs would be on and or off if :
insens350 [35]
Bulbs c and b would still be screwed in if they were in to begin with and bulbs A, D, and E. would be unscrewed
6 0
3 years ago
Read 2 more answers
Worldâs tallest building. suppose that you drop a marble from the top of the burj khalifa building in dubai, which is about 830
-Dominant- [34]
<span>a) 13 seconds b) 130 m/s The formula for the distance an object moves while under constant acceleration is d = 1/2AT^2. So let's define d as 830 m, A as 9.8m/s^2, and solve for T 830 m = 1/2 9.8 m/s^2 T^2 830 m = 4.9 m/s^2 T^2 Divide both sides by 4.9 m/s^2 169.3878 s^2 = T^2 Take the square root of both sides 13.01491 s = T Since we only have 2 significant figures, round the result to 13 seconds which is the answer to the first part of the question. To find out how fast the marble is moving, just multiply T and A together 13 s * 9.8 m/s^2 = 127.4 m/s Since we only have 2 significant figures, round the result to 130 m/s.</span>
7 0
4 years ago
Find the magnitude of the vector v given its initial and terminal points. Round your answer to four decimal places.
Sliva [168]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is |v| = 6.93

Explanation:

From the question we are told that

    The initial point is (x_1 , y_1 , z_1 ) = (-1 , 7 , 4 )

    The  terminal point is  (x_2 , y_2 , z_2) = (-5 , 11, 8 )

Generally the magnitude of the vector is mathematically represented as

     |v| = \sqrt{(x_2 -x_1 )^2 + (y_2 - y_1 )^2 + (z_2 -z_1)^2}

=>   |v| = \sqrt{(-5 -(-1) )^2 + (11 - 7 )^2 + (8 -4)^2}

=>   |v| = 6.93

3 0
3 years ago
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