3 years ago

Which is one physical property that all stars have

1 answer:

6 0

Answer:

Star characteristics consider physical characteristics such as stellar mass, size, surface temperature, and luminosity .

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1. What is the most common type of distribution? How does this distribution<br> benefit the species?

timurjin [86]

Answer:

Clumped distribution is the most common type of dispersion found in nature. In clumped distribution, the distance between neighboring individuals is minimized.

6 0

3 years ago

Read 2 more answers

Most rocks contain more than one type of

ValentinkaMS [17]

Answer: Mineral

Explanation:

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4 years ago

One the energy level diagram what is represented by the letter<br> a<br> b<br> c

Mademuasel [1]

Answer:

see below

Explanation:

B is the activation energy

A is the enthalpy change which is negative

C is the product of oxygen and ethanol which is carbon dioxide and water

hope this helps, please mark

3 0

4 years ago

A skier of mass 70 kg is pulled up a slope by a motor-driven cable. The acceleration of gravity is 9.8 m/s 2 . How much work is

mote1985 [20]

Answer:26.65 kJ

Explanation:

Given

mass of skier=70 kg

length of ramp=62.5 m

slope $=38.4 ^{\circ}$

speed=3.77 m/s

so net force on skier must be zero

Net work done will be change in Potential energy of skier

Potential Energy $=mg(\Delta H)$

$\Delta H=62.5sin38.4=38.821 m$

$P.E.=70\times 9.81\times 38.82=26,658.88 J$

P.E.=26.65 kJ

4 0

4 years ago

Learning Goal: To be able to calculate work done by a constant force directed at different angles relative to displacement

svlad2 [7]

Answer:

Woke done, W = 4156.92 Joules

Explanation:

The work done by the force can be calculated as :

$W=F\times s$

$W=Fs\ cos\theta$

$\theta$ is the angle between force and the displacement

It is assumed to find the work done for the given parameters i.e.

Force, F = 30 N

Distance travelled, s = 160 m

Angle between force and displacement, $\theta=30$

Work done is given by :

$W=Fs\ cos\theta$

$W=30\times 160\ cos(30)$

W = 4156.92 Joules

So, the work done by the object is 4156.92 Joules. Hence, this is the required solution.

5 0

3 years ago