Answer:
0.82052 m
Explanation:
potential energy of spring = kinetic energy
=> 0.5kx^2 = 0.5mv^2
=> 

v= 3.11127 m/s
angle = 37°
thus height = distance×sin(37) = D×0.60182
Also,
m×g×h = 0.5×m×v^2
=> 2×9.8×D×0.60182 = 0.5×2×3.11127×3.11127
=> D = 0.82052 m
To determine the Force it is necessary that Samantha starts from the consideration of the dynamic balance between the forces acting on the car. For this, the centripetal force must be equal to the friction force (otherwise the car would lose contact with the ground), the expression of these two forces would be


Here,
= Coefficient of kinematic friction
m = mass
g = Acceleration due to gravity
v = Velocity
r = Radius
From this relationship then she should assume the following
1) The car travels at a constant speed
2) There is indeed that frictional force between the car and the road
3) There is no loss of mass during displacement
4) The centripetal force must be equal to the frictional force so that the car does not lose contact or slip
5) The radius must be constant
Bulbs c and b would still be screwed in if they were in to begin with and bulbs A, D, and E. would be unscrewed
<span>a) 13 seconds
b) 130 m/s
The formula for the distance an object moves while under constant acceleration is d = 1/2AT^2. So let's define d as 830 m, A as 9.8m/s^2, and solve for T
830 m = 1/2 9.8 m/s^2 T^2
830 m = 4.9 m/s^2 T^2
Divide both sides by 4.9 m/s^2
169.3878 s^2 = T^2
Take the square root of both sides
13.01491 s = T
Since we only have 2 significant figures, round the result to 13 seconds which is the answer to the first part of the question. To find out how fast the marble is moving, just multiply T and A together
13 s * 9.8 m/s^2 = 127.4 m/s
Since we only have 2 significant figures, round the result to 130 m/s.</span>
Complete Question
The complete question is shown on the first uploaded image
Answer:
The value is 
Explanation:
From the question we are told that
The initial point is 
The terminal point is 
Generally the magnitude of the vector is mathematically represented as

=> 
=> 