Answer:
0.37 g
Explanation:
The molecular weight for Glycerol = 92
Number of Carbon atoms in glycerol (x) 
= 3
Molecular weight of the Biomass ( Klebsiella aerogenes )
= 
= 
= 26.1
From the molecular weight of the Biomass, we can deduce the Degree of reduction for the substrate(glycerol denoted as 
) as follows:
= (4×1)+(1×1.73)-(2×0.43)-(3×0.24)
= 4.15
Given that the yield of the Biomass = 0.40 g
However;
C = 
C = 
C = 1.41 g
Now , the oxygen requirement can be calculated as:
= 
= 
= 2.1 g/mol
Hence, we can say that the needed oxygen = 2.1 g/mol of the substrate consumed.
Now converting it to mass terms; we have:
= 
= 
= 0.3652 g
≅ 0.37 g
∴ The oxygen requirement for this culture in mass terms = 0.37 g
To determine the number of moles(n) of a substance, divide its amount given in grams by the molar mass. The element in the problem is gold (Au) which has a molar mass of 196.97 grams per mole. The division is better illustrated below
n = 35.12 g / 196.97 grams per mole
The answer to the operation above is 0.1783 moles. Therefore, there are approximately 0.1783 moles of Au in 35.12 grams.
Steps:
Mw = w * R * T / p * V
T = 88 + 273 => 361 K
p = 975 mmHg in atm :
1 atm = 760 mmHg
975 mmg / 760 mmHg => 1.28 atm
Therefore:
= 0.827 * 0.0821 * 361 / 1.28 * 0.270
= 24.51 / 0.3456
molar mass = 70.92 g/mol
Answer : The pressure it exert under these new conditions will be, 87 atm
Explanation :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 19 atm
= final pressure of gas = ?
= initial volume of gas = 100 L
= final volume of gas = 20 L
= initial temperature of gas = 
= final temperature of gas = 
Now put all the given values in the above equation, we get:
Therefore, the pressure it exert under these new conditions will be, 87 atm
