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gladu [14]
3 years ago
7

3Fe + 4H2O Fe3O4 + 4H2

Chemistry
2 answers:
amid [387]3 years ago
6 0

Explanation:

3Fe + 4H_2O\rightarrow Fe_3O_4 + 4H_2

According to reaction, 3 atoms of iron reacts with 4 molecules of water to give 1 molecule of ferric oxide and 4 molecules of hydrogen gas.

Number of molecules of hydrogen gas =Stoichiometric coefficient ofH_2

= 4 molecules

4 molecules of hydrogen gas are produced.

According to reaction, 4 molecules of water reacts with 3 atoms of iron.

And in 1 molecule of water there are 2 oxygen atoms.

Then 4 molecules of water have = 4 × 2 = 8 atoms of oxygen

4 oxygen atoms are required.

the given reaction can also be read as,According to reaction, 3 moles of iron reacts with 4 moles of water to give 1 mole of ferric oxide and 4 moles of hydrogen gas.

1 moles of Fe_3O_4 are formed.

Moles of Fe_3O_4 = 1

Moles of H_2O = 4

Mole ratio of Fe to H_2O = \frac{1}{4}

Mole ratio of Fe to H_2O is 1:4.

According to reaction, 4 molecules of water reacts with 3 atoms of iron.

And in 1 molecule of water there are 1 hydrogen atoms.

Then 4 molecules of water have = 4 × 1 = 4 atoms of hydrogen.

4 hydrogen atoms are involved in this reaction

aalyn [17]3 years ago
3 0
<span>These are five questions with its five answers.
</span><span>
</span><span>
</span><span>First, we have to explain main question.
</span>
<span /><span /><span>
</span><span>The statement provides the chemical equation for the reaction of Fe with water to produce iron(III) oxide and hydrogen.
</span>
<span /><span /><span>
</span><span>Fe3O4 is a weird chemical formula. It belongs to the product named oxoiron.
</span>
<span /><span /><span>
Next, I have to tell how you must interpret the question. The five questions are based on the complete reaction of the same number of moles as the coefficients indicated in the chemical equation.
</span><span />

<span>Those coefficients are 3 for Fe, 4 for H₂O, 1 for Fe₃O₄ and 4 for H₂.


With that understood, let's work every question.


1) How many molecules of H₂ are produced?


Answer: 4 moles of molecules.

</span><span>Justification:
</span>

<span /><span /><span>This is, the number of moles of H₂ produced is given by the coefficient indicated in the chemical equation.
</span><span />

<span>2) How many oxygen atoms are required?
</span><span />

<span>Answer: 4.

</span><span>This is, the atoms of oxygen are supplied in the molecules of water. Since the coeffcient of water is 4, and each molecule o fwater has 1 atom of oxygen, 4 moles of water contain 4 moles of atoms of oxygen.
</span>
<span /><span /><span>
3) How many moles of Fe₃O₄ are formed?
</span><span />

<span>Answer: 1.
</span><span />

<span>Justification: the coefficient of for formula Fe₃O₄ is 1, indicating that the theoretical yield is 1 mol of molecules.
</span><span />

<span>4) What is the mole ratio of Fe to H₂O?
</span><span />

<span>Answer: 3:4
</span><span />

<span>Justification:
</span><span>
</span><span>
</span><span>The ratio is the quotient of the two coefficients: the coefficient of the Fe divided by the coefficient of the H₂O.
</span>
<span /><span /><span>
5) How many hydrogen atoms are involved in this reaction?
</span><span />

<span>Answer: 8 moles of hydrogen atoms.
</span><span />

<span>Justification: as you can see each molecule of H₂O has 2 atoms of hydrogen, then 4 moles of molecules of H₂O have 8 moles of atoms of hydrogen. And of course the same number are in the produt: 4 moles of H₂ contain 8 moles of atomos of hydrogen
</span><span>
</span><span>
</span>
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kicyunya [14]
I would say #3 I’m sorry if it’s wrong tho
4 0
2 years ago
Which of the following 0.820 M solutions would have the greatest colligative effect?
eimsori [14]

Answer:

K3PO4

Explanation:

Recall that colligative properties depends on the number of particles present. The greater the number of particles present, the greater the degree of colligative properties of the solution. Let us look at each option individually;

SrCr2O7-------> Sr^2+ + Cr2O7^2- ( 2 particles)

C4H11N (not ionic in nature hence it can not dissociate into ions)

K3PO4-------> 3K^+ + PO4^3- (4 particles)

Rb2CO3-------> 2Rb^+ + CO3^2- (3 particles)

Hence K3PO4 has the greatest number of particles and will display the greatest colligative effect.

8 0
2 years ago
A solution was prepared by mixing 50.0 g
frez [133]

Answer:

4.78 %.

Explanation:

<em>mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.</em>

<em></em>

<em>mass % = (mass of solute/mass of solution) x 100.</em>

<em></em>

mass of MgSO₄ = 50.0 g,

mass of water = d.V = (0.997 g/mL)(1000.0 mL) = 997.0 g.

mass of the solution = mass of water + mass of MgSO₄ = 997.0 g + 50.0 g = 1047.0 g.

<em>∴ mass % = (mass of solute/mass of solution) x 100</em> = (50.0 g/1047.0 g) x 100 = <em>4.776 % ≅ 4.78 %.</em>

4 0
3 years ago
As changes in energy levels of electrons increase, the frequencies of atomic line spectra they emit ___?
Tju [1.3M]

Ans: As changes in energy levels of electrons increase, the frequencies of atomic line spectra they emit will <u>increase.</u>

The energy (E) is related to the frequency (ν) by the following equation:

E = hν

where h = planck's constant

The change in energy i between levels is:

ΔΕ = h(Δν)  -----(1)

Based on the above equation, as the changes in energy levels increase, the frequency of emitted radiation will also increase.



6 0
3 years ago
At what temperature is the following reaction feasible: HCl(g) + NH3(g) -&gt; NH4Cl(s)?
Nutka1998 [239]
Energy is distributed not just in translational KE, but also in rotation, vibration and also distributed in electronic energy levels (if input great enough, bond breaks).

All four forms of energy are quantised and the quanta ‘gap’ differences increases from trans. KE ==> electronic.

Entropy (S) and energy distribution: The energy is distributed amongst the energy levels in the particles to maximise their entropy.

Entropy is a measure of both the way the particles are arranged AND the ways the quanta of energy can be arranged.

We can apply ΔSθsys/surr/tot ideas to chemical changes to test feasibility of a reaction:

ΔSθtot = ΔSθsys +  ΔSθsurr

ΔSθtot must be >=0 for a chemical change to be feasible.

For example: CaCO3(s) ==> CaO(s) + CO2(g) 

ΔSθsys = ΣSθproducts – ΣSθreactants 

ΔSθsys = SθCaO(s) + SθCO2(g) – SθCaCO3(s) 

ΔSθsurr is –ΔHθ/T(K) and ΔH is very endothermic (very +ve),

Now ΔSθsys is approximately constant with temperature and at room temperature the ΔSθsurr term is too negative for ΔSθtot to be plus overall.

But, as the temperature is raised, the ΔSθsurr term becomes less negative and eventually at about 800oCΔSθtot becomes plus overall (and ΔGθ becomes negative), so the decomposition is now chemically, and 'commercially' feasible in a lime kiln.

CaCO3(s) ==> CaO(s) + CO2(g)  ΔHθ = +179 kJ mol–1  (very endothermic)

This important industrial reaction for converting limestone (calcium carbonate) to lime (calcium oxide) has to be performed at high temperatures in a specially designed limekiln – which these days, basically consists of a huge rotating angled ceramic lined steel tube in which a mixture of limestone plus coal/coke/oil/gas? is fed in at one end and lime collected at the lower end. The mixture is ignited and excess air blasted through to burn the coal/coke and maintain a high operating temperature.
ΔSθsys = ΣSθproducts – ΣSθreactants
ΔSθsys = SθCaO(s) + SθCO2(g) – SθCaCO3(s) = (40.0) + (214.0) – (92.9) = +161.0 J mol–1 K–1
ΔSθsurr is –ΔHθ/T = –(179000/T)
ΔSθtot = ΔSθsys +  ΔSθsurr
ΔSθtot = (+161) + (–179000/T) = 161 – 179000/T
If we then substitute various values of T (in Kelvin) you can calculate when the reaction becomes feasible.
For T = 298K (room temperature)

ΔSθtot = 161 – 179000/298 = –439.7 J mol–1 K–1, no good, negative entropy change

For T = 500K (fairly high temperature for an industrial process)

ΔSθtot = 161 – 179000/500 = –197.0, still no good

For T = 1200K (limekiln temperature)

ΔSθtot = 161 – 179000/1200 = +11.8 J mol–1 K–1, definitely feasible, overall positive entropy change

Now assuming ΔSθsys is approximately constant with temperature change and at room temperature the ΔSθsurr term is too negative for ΔSθtot to be plus overall. But, as the temperature is raised, the ΔSθsurr term becomes less negative and eventually at about 800–900oC ΔSθtot becomes plus overall, so the decomposition is now chemically, and 'commercially' feasible in a lime kiln.
You can approach the problem in another more efficient way by solving the total entropy expression for T at the point when the total entropy change is zero. At this point calcium carbonate, calcium oxide and carbon dioxide are at equilibrium.
ΔSθtot–equilib = 0 = 161 – 179000/T, 179000/T = 161, T = 179000/161 = 1112 K

This means that 1112 K is the minimum temperature to get an economic yield. Well at first sight anyway. In fact because the carbon dioxide is swept away in the flue gases so an equilibrium is never truly attained so limestone continues to decompose even at lower temperatures.

8 0
2 years ago
Read 2 more answers
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