The answer to the question is boneless
Answer:
No, a triangle cannot be constructed with sides of 2 in., 3 in., and 6 in.
For three line segments to be able to form any triangle you must be able to take any two sides, add their length and this sum be greater than the remaining side.
2
in.
+
3
in.
=
5
in.
5
in.
<
6
in.
For a triangle with sides 3 in., 4 in. and 5 in. which can form a triangle:
3 + 4 = 7 which is greater than 5
3 + 5 = 8 which is greater than 4
4 + 5 = 9 which is greater than 3
Step-by-step explanation:
Answer:
9.25 or or 9 1/4
Step-by-step explanation:
The graph is Parabola or Graph of Quadratic Function.
The graph has minimum value, not maximum. So ( A ) is not correct for maximum part.
B is not correct for exponential part.
also C is not correct for discrete part as Quadratic graph is continuous.
So the answer is D.
Answer: See the picture attached.
Step-by-step explanation:
Given the following mixed numbers:
You need to convert them to decimal numbers. The steps to do this are shown below:
1. Divide the numerator of the fraction by the denominator.
2. Add the quotient obtained to the whole number part.
Then:
Therefore, the point is:
Where 
is the x-coordinate and 
is the y-coordinate.
Knowing this, you can plot it on the coordinate plane, as you can see in the picture attached.
