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DaniilM [7]
3 years ago
12

PLEASE HELP!Find the slope of the line on the graph.

Mathematics
2 answers:
GrogVix [38]3 years ago
3 0

Answer:

3/1 or 3

Step-by-step explanation:

It rises up three and to the side one

Kipish [7]3 years ago
3 0

Answer: The slope is 3.

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What is the power to another power rule
Sholpan [36]

Answer:

9

Step-by-step explanation:

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3 years ago
Read 2 more answers
The data shown in the table below can be
nignag [31]
Hello there! The missing y-values are 12, 14, and 16.

Given all our x-values and two additional y-values, we can see that multiplying the x-value by 2 gives us the y-value. This is shown when x is 5 and 9, because multiplying 5 by 2 gave us 10, and multiplying 9 by 2 gave us 18. Because of this rule, we can multiply each given x-value by 2 to receive our y-value. Once solving, we also notice that the y-values all add by 2 to get the next factor as the data number increases. Hope this helps!
8 0
2 years ago
The print on the package of -watt General Electric soft-white light-bulbs says that these bulbs have an average life of hours. A
Naddika [18.5K]

Answer:

Hi your question is incomplete attached below is the complete question

answer : p ( X < 725 )  = 0.0116

Step-by-step explanation:

Given data:

Average life of bulbs (μ  ) = 750 hours

standard deviation (б ) = 55 hours

n ( sample size ) = 25

X = 725  

<u>Probability that the mean life of a random sample of 25 bulbs will be less than725 hours </u>

p ( X < 725 ) = p (( X - μ )/ б √n  <  725 - 750 / 55√25 )

                     = P ( Z > - 2.27 )

Hence P ( X < 725 ) = 0.0116  ( using Z-table )

3 0
3 years ago
The decay of 192 mg of an isotope is given by A(t)= 192e-0.015t, where t is time in years. Find the amount left after 55 years.R
finlep [7]
This is a typical radioactive decay problem which uses the general form:

A = A0e^(-kt)

So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:

A = 192e^(-0.015*55)
<em>A = 84 mg</em>
6 0
3 years ago
Find the measure for &lt; MQX<br><br> 54<br> 59<br> 63<br> 65
vivado [14]
3x+39=5x+29
x=5
3(5)+39=54
5(5)+29=54
A) 54°
8 0
3 years ago
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