I think the answer the students average is 15 km?
Putting them in that oder can be absolutely wrong becaus they are not in the same group of the periodic table
The combustion of naphthalene is given as:
C10H8 (s) + 12 O2 (g) --> 10CO2 (g) + 4 H2O (l)
Enthalpy of combustion ΔH = -5157 kJ/mol
Now, the enthalpy change of a reaction is given
ΔH = ∑nΔHf (products) - ∑nΔHf (reactants)
where n = number of moles
ΔHf = enthalpy of formation
Therefore,
ΔH = [10*ΔHf(CO2) + 4*ΔHf(H2O)] - [1*ΔHf(C10H8) + 12*O2]
-5157 = [10*(-393.5) + 4*(285.83)] - [ΔHf(C10H8) + 12*(0)]
ΔHf(C10H8) = 78.68 kJ/mol
(2.5)(10000)=25000
25000 * 3785
ML = 94635294.6 milliliters
Explanation:
non zeores digits always significant any zero between two significant digits are significant a final zeros in the decimal portion only are significant
