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VikaD [51]
3 years ago
12

Find the polar coordinates corresponding to a point located at (−6.48, 12.58) in Cartesian coordinates

Physics
1 answer:
barxatty [35]3 years ago
5 0

Answer:

Explanation:

r = √(-6.48² + 12.58²) = 14.1508586311... 14.15

θ = arctan(12.58 / -6.48) = 117.25314692... 117.25

(r, θ) = (14.15, 117.25)

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Electromagnetic induction
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Where have you heard the word calorie before what do you think a calorie is
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Answer:

Explanation:

Calorie is a common term used to describe the amount of energy that can be derived from food products.

We quantify foods based on the calories of energy they possess. A high calorific food will yield more energy to the body and is often desired for intense physical activities.

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There are two cars moving at a constant speed. Car A is moving constantly at 5 m/s on a straight path. Car B is moving constantl
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Answer:

The car moving with constant speed on the path with a deep curve experiences an acceleration towards the center of the curve.

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4 years ago
What parts of the geosphere are involved in plate tectonics
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8 0
3 years ago
Temperature and pressure of a region upstream of a shockwave are 295 K and 1.01* 109 N/m². Just downstream the shockwave, the te
seraphim [82]

Answer:

change in internal energy 3.62*10^5 J kg^{-1}

change in enthalapy  5.07*10^5 J kg^{-1}

change in entropy 382.79 J kg^{-1} K^{-1}

Explanation:

adiabatic constant \gamma =1.4

specific heat is given as =\frac{\gamma R}{\gamma -1}

gas constant =287 J⋅kg−1⋅K−1

Cp = \frac{1.4*287}{1.4-1} = 1004.5 Jkg^{-1} k^{-1}

specific heat at constant volume

Cv = \frac{R}{\gamma -1} = \frac{287}{1.4-1} = 717.5 Jkg^{-1} k^{-1}

change in internal energy = Cv(T_2 -T_1)

                            \Delta U = 717.5 (800-295)  = 3.62*10^5 J kg^{-1}

change in enthalapy \Delta H = Cp(T_2 -T_1)

                                 \Delta H = 1004.5*(800-295) = 5.07*10^5 J kg^{-1}

change in entropy

\Delta S =Cp ln(\frac{T_2}{T_1}) -R*ln(\frac{P_2}{P_1})

\Delta S =1004.5 ln(\frac{800}{295}) -287*ln(\frac{8.74*10^5}{1.01*10^5})

\Delta S = 382.79 J kg^{-1} K^{-1}

7 0
3 years ago
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