<h3>
Answer:</h3>
0.34 mol S
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
11 g S
<u>Step 2: Identify Conversions</u>
[PT] Molar Mass of S - 32.07 g/mol
<u>Step 3: Convert</u>
- Set up:
- Multiply/Divide:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
0.343 mol S ≈ 0.34 mol S
Answer:
The absorbance of the myoglobin solution across a 1 cm path is 0.84.
Explanation:
Beer-Lambert's law :
Formula used :
where,
A = absorbance of solution
c = concentration of solution
= Molar absorption coefficient
l = path length
= incident light
= transmitted light
Given :
l = 1 cm, c = 1 mg/mL ,
Molar mass of myoglobin = 17.8 kDa = 17.8 kg/mol=17800 g/mol
(1 Da = 1 g/mol)
c = 1 mg /mL = 
1 mg = 0.001 g, 1 mL = 0.001 L
The absorbance of the myoglobin solution across a 1 cm path is 0.84.
Answer:
27.98g/mol
Explanation:
Using ideal gas law equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
T = temperature (K)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
According to the information given:
V = 2.5L
P = 1.4 atm
T = 282K
n = ?
Using PV = nRT
n = PV/RT
n = 1.4 × 2.5/0.0821 × 282
n = 3.5/23.1522
n = 0.151mol
Using the formula to calculate molar mass of the elemental gas:
mole = mass/molar mass
Molar mass = mass/mole
Molar mass = 4.23g ÷ 0.151mol
Molar mass = 27.98g/mol
1.) <span>2Na(aq)+2H2O(l)→2NaOH(aq)+H2(g),
Na is oxidizing agent and H is reducing agent.
2.) </span><span>C(s)+O2(g)→CO2(g)
C is an oxidizing agent
3.) </span><span>2MnO−4(aq)+5SO2(g)+2H2O(l)→2Mn2+(aq)+5SO2−4(aq)+4H+(aq)
Mn is reducing agent and S is oxidizing agent.</span>
