Question

At 1.0atm a gas has a volume of 36.7 L, what is the volume at 5.3atm?

Answer 1

Answer:

$V_2=6.92L$

Explanation:

Hello,

In this case, we use the Boyle's law to understand the volume-pressure relationship as an inversely proportional relationship:

$P_1V_1=P_2V_2$

In such a way, we compute the resulting final volume as shown below:

$V_2=\frac{P_1V_1}{P_2}=\frac{1.0atm*36.7L}{5.3atm} \\\\V_2=6.92L$

Best regards.