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fredd [130]
3 years ago
8

Can metal be recognised as a good heat shield? why or why not?? ​

Chemistry
2 answers:
fiasKO [112]3 years ago
4 0

Answer:

In summary, because of metal's unique properties, it can be an excellent heat shield (such as when aluminum foil is wrapped around warm food) or an excellent heat sink (such as when metals fins are attached to computer chips).

Molodets [167]3 years ago
3 0

Explanation:

Convection requires a fluid material that can move around. Typically, metals are solid, not fluid, and therefore do not participate in convection. ... This means that metal can be either a good heat shield, a mediocre heat shield, or a bad heat shield, depending on how we use it.

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What volumes of 0.200 M HCOOH and 2.00 M NaOH would make 500. mL of a buffer with the same pH as one made from 475 mL of 0.200 M
Fed [463]

<u>36 ml of NaOh and</u><u> 464 ml</u><u> of </u><u>HCOOH</u><u> would be enough to form 500 ml of a buffer with the same pH as the buffer made with </u><u>benzoic acid </u><u>and NaOH.</u>

What is benzoic acid found in?

  • Some natural sources of benzoic acid include: ​Fruits:​ Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
  • ​Spices:​ Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.

Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.

Amount of moles of NaOH -2 × 0.025 =  0.05 mol

Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol

In this case, we can calculate the pH produced by the buffer of these two reagents, as follows

pH = pKa + log\frac{base}{acid}

4.2 + log\frac{0.05}{0.045} = 4.245

We must repeat this calculation, with the values shown for HCOOH and NaOH. In this case, we can calculate as follows

pH = pKa + log\frac{base}{acid}

4.245 = 3.75 + log\frac{base}{acid}

log\frac{base}{acid} = 0.5

\frac{base}{acid} = 3.162

Now we must solve the equation above. This will be done using the following values

\frac{2(0.5 - x)}{0.2x - 2(0.5 - x)} = 0.464 L

With these values, we can calculate the volumes of NaOH and HCOOH needed to make the buffer.

NaOH volume

( 0.5 - 0.464)L

0.036L .................... 36ml

HCOOH volume

500 - 36 = 464mL

Learn more about benzoic acid

brainly.com/question/24052816

#SPJ4

3 0
2 years ago
What happens to a hill due to wind blown sand
Wewaii [24]
I'd say that the answer is erosion
3 0
3 years ago
Sodium phosphate and calcium chloride react to form sodium chloride and calcium phosphate. If you have 379.4 grams of calcium ch
barxatty [35]

Answer: 353.6 g.


Explanation:


1) Word equation (given)

Sodium phosphate + calcium choride → sodium chloride + calcium phosphate


2) Balanced chemical equation

2 Na₃PO₄ +3 CaCl₂ → 6 NaCl + Ca₃(PO4)₂


3) Mole ratio

2 moles Na₃PO₄ : 3 moles CaCl₂ :  6 moles NaCl : 1 mole Ca₃(PO4)₂


4)  Formula to convert grams to moles

number of moles = mass in grams / molar mass


5) Number of moles of limiting reactant

a) mass in grams = 379.4 g CaCl₂

b) molar mass CaCl₂ = 110.98 g/mol

c) number of moles CaCl₂ = 379.4 g / 110.98 g/mol = 3.419 moles


6) Theoretical yield of Ca₃(PO4)₂

    3 moles CaCl₂ / 1 mole Ca₃(PO4)₂ = 3.419 moles CaCl₂ / x ⇒

    x = 3.419 × 1 / 3 = 1.140 moles Ca₃(PO4)₂


7) Convert 1.140 moles Ca₃(PO4)₂

a) molar mass Ca₃(PO4)₂ = 310.1767 g/mol

b) mass in grams = number of moles × molar mass = 1.140 moles × 310.1767 g/mol = 353.6 g ← answer.

7 0
4 years ago
Here is my question..
OverLord2011 [107]
I would say 3.0 cause yeah yeah yeah yeah I’m iann Dior
7 0
3 years ago
Read 2 more answers
A compound is found to contain 73.23% xenon name 26.77% oxygen by mass. What is the empirical formula for this compound ?
Luba_88 [7]

The empirical formula is XeO₃.

<u>Explanation:</u>

Assume 100 g of the compound is present. This changes the percents to grams:

Given mass in g:

Xenon = 73.23 g

Oxygen = 26.77 g

We have to convert it to moles.

Xe = 73.23/   131.293 = 0.56 moles

O = 26.77/ 16 = 1.67 moles

Divide by the lowest value, seeking the smallest whole-number ratio:

Xe = 0.56/ 0.56 = 1

O = 1.67/ 0.56 = 2.9 ≈3

So the empirical formula is XeO₃.

6 0
3 years ago
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