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Nikitich [7]
3 years ago
11

What pattern do you see as you compare elements that belong in groups IA to VIIIA on the

Chemistry
1 answer:
topjm [15]3 years ago
5 0
Group IA are metals and all react vigorously because they have 1 valence electron in their outer most shell and the reactivity increases as you go down the group. Group VIIIA are non reactive because of their complete valence shell.
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The ability of carbon to attract electrons is
Gelneren [198K]
Less than that of nitrogen and oxygen remember cnof "see noff" . this is the order of electronegativity carbon is less than nitrogen which is less than oxygen which is less than fluorine.
5 0
3 years ago
Natural gas burns in air to form carbon dioxide and water, releasing heat. CH4(g)+2O2(g)→CO2(g)+2H2O(g) ΔHrxn = -802.3 kJ.
Olenka [21]

Answer:

1) Minimum mass of methane required to heat 45.0 g of water by 21.0°C is 0.0788 g.

2) Minimum mass of methane required to heat 50.0 g of water by 26.0°C is 0.108 g.

Explanation:

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g) ,\Delta H_{rxn} =-802.3 kJ

1) Minimum mass of  methane required to raise the temperature of water by 21.0°C.

Mass of water = m = 45.0 g

Specific heat capacity of water = c = 4.18 J/g°C

Change in temperature of water = ΔT = 21.0°C.

Heat required to raise the temperature of water by 21.0°C = Q

Q=mc\Delta T= 45.0 g\times 4.18 J/g^oC\times 21.0^oC

Q = 3,950.1 J = 3.9501 kJ

According to reaction 1 mole of methane on combustion gives 802.3 kJ of heat.

Then 3.950.1 kJ of heat will be given by:

=\frac{3.950.1 kJ}{802.3 kJ}=0.004923 mol

Mass of 0.004923 moles of methane :

0.004923 mol × 16 g/mol=0.0788 g

Minimum mass of methane required to heat 45.0 g of water by 21.0°C is 0.0788 g.

2) Minimum mass of  methane required to raise the temperature of water by 26.0°C.

Mass of water = m = 50.0 g

Specific heat capacity of water = c = 4.18 J/g°C

Change in temperature of water = ΔT = 26.0°C.

Heat required to raise the temperature of water by 21.0°C = Q

Q=mc\Delta T= 50.0 g\times 4.18 J/g^oC\times 26.0^oC

Q = 5,434 J= 5.434 kJ

According to reaction 1 mole of methane on combustion gives 802.3 kJ of heat.

Then 5.434 kJ of heat will be given by:

=\frac{5.434 kJ}{802.3 kJ}=0.006773 mol

Mass of 0.006773 moles of methane :

0.006773 mol × 16 g/mol= 0.108 g

Minimum mass of methane required to heat 50.0 g of water by 26.0°C is 0.108 g.

6 0
4 years ago
True or False: <br><br> Rain is the only form of precipitation that this pollutant takes.​
Nady [450]

Answer:

I’m not sure probably false

Explanation:

4 0
3 years ago
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We love blasting our radio in the morning to wake up. Radio waves are used to transmit information on various channels. Calculat
Reil [10]

Answer:

wavelength =  0.56 × 10⁻² m

Explanation:

Given data:

Frequency of radiation = 5.4 × 10¹⁰ Hz

Wavelength = ?

Solution:

Formula:

speed of light = wavelength × frequency

wavelength = speed of light / frequency

wavelength =  3 × 10⁸ m/s / 5.4 × 10¹⁰ Hz     ( Hz= 1/s)

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4 0
3 years ago
What should you do if your hypothesis is incorrect ?
Paladinen [302]

Answer:

come to a conclusion

Explanation:

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