Deposition is geological process of sediments, soil and rocks that are added to land-form or land mass. Wind, ice, water, and gravity transport weathered surface material, which, at the loss of enough kinetic energy in the fluid, is deposited. Technically Building up layers of sediment.
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Answer:-4/-6. Simplify to 2/3
Explanation:
Y2-Y1/X2-X1=slope
Answer: (a) The work done by this force on the particle is 42.71 J.
(b) The change in the potential energy of the system is -42.71 J.
(c) The kinetic energy the particle is 62.96 J.
Explanation:
(a) For the given situation, expression for work done is as follows.
W = 
= 
= ![[2\frac{x^{2}}{2} + 4x]^{5.15}_{0.9}](https://tex.z-dn.net/?f=%5B2%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%20%2B%204x%5D%5E%7B5.15%7D_%7B0.9%7D)
= 
= ![[(5.15)^{2} + 4(5.15) - (0.9)^{2} - 4(0.9)]](https://tex.z-dn.net/?f=%5B%285.15%29%5E%7B2%7D%20%2B%204%285.15%29%20-%20%280.9%29%5E%7B2%7D%20-%204%280.9%29%5D)
= 26.52 + 20.6 - 0.81 - 3.6
= 42.71 J
Hence, the work done by this force on the particle is 42.71 J.
(b) Expression for a conservative force is as follows.
F = 
dU = -Fdx
= 
= -42.71 J
Therefore, the change in the potential energy of the system is -42.71 J.
(c) According to the work energy theorem,
W = 
= W

=
where, u = velocity of the mass at x = 0.9 m
u = 3.0 m/s, m = 4.50 kg
As, 
= 
= 62.96 J
Therefore, the kinetic energy the particle is 62.96 J.
y = y 0 + v 0 y t − 1 2 g t 2 . If we take the initial position y 0 to be zero, then the final position is y = 10 m. The initial vertical velocity is the vertical component of the initial velocity: v 0 y = v 0 sin θ 0 = ( 30.0 m / s ) sin 45 ° = 21.2 m / s .
The crowns are your brainliest answers. You can answer questions well, and ask for brainliest. Most of the time, you get them.