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Travka [436]
3 years ago
13

Which are complete descriptions of the momentum of an object? Circle all that apply. a. 2.0 kg/s b. 7.2 kg•m/s, right c. 6.1 kg•

m/s2, down d. 4.2 m/s, east e. 1.9 kg•m/s, west f. 2.3 kg•m/s
Physics
1 answer:
Paul [167]3 years ago
8 0
<span>mutations due to exposure to chemicals</span>
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Heat from the surface is transferred underground by _______.
Ostrovityanka [42]
A, convection, is your answer
5 0
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I’m sorry this is a quiz and we’re correcting it and I still don’t get it anyone know ?
kotegsom [21]

Answer:

3.0M

Explanation:

Thats two wavelengths,not one.

Pretty honest mistake I would've made the same if I was rushing

5 0
3 years ago
what is the necessary condition within the hydrogen atom for balmer line photons to be absorbed by the hydrogen atom
luda_lava [24]

Explanation :

When an electron jumps from one energy level to another, the energy of atom gets changed.

If a photon gets absorbed, the electron will move to higher energy levels and then fall back to the lower energy levels. Then each time a photon will be absorbed whose energy is given by difference between the initial and final energy levels i.e

In Balmer series, the transition is from higher energy levels to n = 2.

So, the necessary condition for Balmer series is that the electron should be at first excited state or n = 2 level as shown in figure.


6 0
3 years ago
Jupiter's moon Io has active volcanoes (in fact, it is the most volcanically active body in the solar system) that eject materia
melisa1 [442]

Answer:

H_2 = 91.55 km

Explanation:

Gravity on the surface of planet is given as

g = \frac{GM}{R^2}

as we know that

M = 8.93 \times 10^{22} kg

R = 1821 km

now gravity on the planet is

g = \frac{(6.67 \times 10^{-11})(8.93 \times 10^{22})}{(1821 \times 10^3)^}

so we have

g = 1.8 m/s^2

now we know that

H_{max} = \frac{v^2}{2g}

so we will say

\frac{H_1}{H_2} = \frac{g_2}{g_1}

\frac{500}{H_2} = \frac{9.81}{1.8}

H_2 = 91.55 km

5 0
3 years ago
Pre-laboratory Assignment: Experiment 20 Reflection and Refraction of Light 1. When light is incident on a reflective surface, w
shusha [124]

Answer:

1) ngle of incidence and reflection are equal,  light carries does not change

2) the angle of this line with respect to the surface is 90º

3) protractor

4)    n₂  sin θ₂ = n_1 sin θ₁,  light ray must have a greater angle than the incident ray ,

Explanation:

1) When light falls on a reflective surface, the angle of incidence and reflection are equal and as it travels in the same medium, the speed that the light carries does not change

2) The normal is a line perpendicular to the point of incidence of light, so the angle of this line with respect to the surface is 90º

3) Angles are measured with a protractor

4) When light passes from one medium to another, the speed of the ray changes due to the difference in the refractive index in each medium, due to this change in speed the transmitted light ray must have a greater angle than the incident ray , since the speed increases as the density of the medium decreases

           \frac{sin \theta _2}{ sin \theta_1} = \frac{v_2}{v_1}

          \frac{c}{v_2} \  sin \theta_2 = \frac{c}{v_1}  \ sin \theta_1

          n₂  sin θ₂ = n_1 sin θ₁

6 0
3 years ago
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