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Tresset [83]
3 years ago
6

An ambulance is traveling north at 55.9 m/s, approaching a car that is also traveling north at 28.4 m/s. The ambulance driver he

ars his siren at a frequency of 983 Hz. The velocity of sound is 343 m/s. At what frequency does the driver of the car hear the ambulance's siren?
Physics
1 answer:
wlad13 [49]3 years ago
6 0

Answer:

915 Hz

Explanation:

The observed frequency from a sound source is given as

f₀ = f [(v + v₀)/(v+vₛ)]

where

f₀ = observed frequency of the sound by the observer = ?

f = actual frequency of the sound wave = 983 Hz

v = actual velocity of the sound waves = 343 m/s

vₛ = velocity of the source of the sound waves = 55.9 m/s

v₀ = velocity of the observer = 28.4 m/s

f₀ = 983 [(343+28.4)/(343+55.9)]

f₀ = 915.2 Hz = 915 Hz

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ddd [48]

<span>We can answer this using the rotational version of the kinematic equations:</span><span>
θ = θ₀ + ω₀<span>t + ½αt²     -----> 1</span></span>

ω² = ω₀² + 2αθ            -----> 2

Where:

θ = final angular displacement = 70.4 rad

θ₀ = initial angular displacement = 0

ω₀ = initial angular speed

ω = final angular speed

t = time = 3.80 s

α = angular acceleration = -5.20 rad/s^2

Substituting the values into equation 1:<span>
70.4 = 0 + ω₀(3.80) + ½(-5.20)(3.80)² </span><span>

ω₀ = (70.4 + 37.544) / 3.80 </span><span>

ω₀ = 28.406 rad/s </span><span>


Using equation 2:
ω² = (28.406)² + 2(-5.2)70.4 


ω = 8.65 rad/s 


</span>

5 0
3 years ago
At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats faci
Klio2033 [76]

Answer:

The radius of a chamber is 2.36 meters.

Explanation:

Given that,

The outer wall moves at a speed of 2.72 m/s.

Mass of the person, m = 75.1 kg

The person feels a force of 235 N force pressing against his back. The force acting on the person is centripetal force. It is given by the below formula :

F=\dfrac{mv^2}{r}

r is the radius of a chamber

r=\dfrac{mv^2}{F}

r=\dfrac{75.1\times (2.72)^2}{235}

r = 2.36 meters

So, the radius of a chamber is 2.36 meters. Hence, this is the required solution.

7 0
3 years ago
The drawings show two examples in which a ray of light is refracted at the interface between two liquids. In each example the in
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Answer:

Possible options:

A. nA, nC, nB

B. nA, nB, nC

C. nC, nB, nA

D. nC, nA, nB

E. nB, nA, nC

Answer is D

Explanation:

When the light is refracted into liquid B it is bent away from the normal, so that nA > nB. When the light is refracted into liquid C it is bent toward the normal, so that nC > nA. Therefore, we conclude that nC > nA > nB

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3 years ago
What is f =ma derivation?<br>​
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3 years ago
Read 2 more answers
What is the minimum coefficient of friction needed for a frightened driver to take the same curve at 20.0 km/h?
Tanya [424]

Answer:

The minimum coefficient of friction is 0.22

Explanation:

Suppose If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the curve.

We need to calculate the ideal speed to take a 85 m radius curve banked at 15°.

Given that,

Radius = 85 m

Angle = 15°

Speed = 20 km/h

We need to calculate the ideal speed

Using formula of speed

\tan\theta=\dfrac{v^2}{rg}

v=\sqrt{rg\tan\theta}

Put the value into the formula

v=\sqrt{85\times9.8\tan15}

v=14.9\ m/s

We need to calculate the minimum coefficient of friction

Using formula for coefficient of friction

v^2=\dfrac{rg(\sin\theta-\mu\cos\theta)}{\mu\sin\theta+\cos\theta}

Put the value into the formula

(5.55)^2=\dfrac{85\times9.8(\sin15-\mu\cos15)}{\mu\sin15+\cos15}

\dfrac{30.8025}{85\times9.8}=\dfrac{0.2588-\mu0.966}{\mu0.2588+0.966}

0.9754462\ mu-0.223541=0

\mu=\dfrac{0.223541}{0.9754462}

\mu=0.22

Hence, The minimum coefficient of friction is 0.22

3 0
3 years ago
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