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Alekssandra [29.7K]

3 years ago

9

A hiker begins a trip by first walking 22.2 km

1 answer:

Dominik [7]3 years ago

4 0

9514 1404 393

Answer:

20.6 km

Step-by-step explanation:

Using (East, North) coordinates, the hiker's position ends up being ...

22.2(cos(-45°), sin(-45°)) +40.1(cos(65°), sin(65°))

We're only interested in the second coordinate of this total, which is ...

22.2sin(-45°) +40.1sin(65°) ≈ -15.698 +36.343 = 20.645 . . . km

The y-component of the hiker's position at the end of the second day is 20.6 km north of her starting location.

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What expression is equivalent to 8/9 divided 3/4

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3 years ago

Problem Solving (M1) About 100,000 people live in a town. The number 100,000 can be written as 10n, where n is a whole number. W

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Answer:

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Step-by-step explanation:

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3 years ago

Help based offf order of operations please help

JulijaS [17]

Answer:

The answer for :

$h. \: \: \: \frac{5}{6}$

$i. \: \: \: \frac{35}{32}$

$k. \: \: \: \frac{-29}{20}$

$l. \: \: \: \frac{13}{15}$

Step-by-step explanation:

Question h:

$\frac{2}{3} + ( \frac{1}{3} \times \frac{1}{2} )$

$= \frac{2}{3} + \frac{1}{6}$

$= \frac{2 \times 2}{3 \times 2} + \frac{1}{6}$

$= \frac{4}{6} + \frac{1}{6}$

$= \frac{5}{6}$

Question i:

$\frac{7}{8} + \frac{1}{4} \times ( \frac{3}{2} - \frac{5}{8} )$

$= \frac{7}{8} + \frac{1}{4} \times ( \frac{3 \times 4}{2 \times 4} - \frac{5}{8} )$

$= \frac{7}{8} + \frac{1}{4} \times ( \frac{12}{8} - \frac{5}{8} )$

$= \frac{7}{8} + (\frac{1}{4} \times \frac{7}{8} )$

$= \frac{7}{8} + \frac{7}{32}$

$= \frac{7 \times 4}{8 \times 4} + \frac{7}{32}$

$= \frac{28}{32} + \frac{7}{32}$

$= \frac{35}{32}$

Question k:

$\frac{3}{4} - ( \frac{12}{7} \div \frac{12}{21} ) + \frac{4}{5}$

$= \frac{3}{4} - ( \frac{12}{7} \times \frac{21}{12} ) + \frac{4}{5}$

$= \frac{3}{4} - \frac{3}{1} + \frac{4}{5}$

$= \frac{3 \times 5}{4 \times 5} - \frac{3 \times 20}{1 \times 20} + \frac{4 \times 4}{5 \times 4}$

$= \frac{15}{20} - \frac{60}{20} + \frac{16}{20}$

$= - \frac{29}{20}$

Question l:

$\frac{5}{2} \times ( \frac{2}{3} - \frac{1}{5} ) - ( \frac{2}{5} \div \frac{4}{3} )$

$= \frac{5}{2} \times ( \frac{2 \times 5}{3 \times 5} - \frac{1 \times 3}{5 \times 3} ) - ( \frac{2}{5} \times \frac{3}{4} )$

$= \frac{5}{2} \times ( \frac{10}{15} - \frac{3}{15} ) - \frac{3}{10}$

$= (\frac{5}{2} \times \frac{7}{15}) - \frac{3}{10}$

$= \frac{7}{6} - \frac{3}{10}$

$= \frac{7 \times 5}{6 \times 5} - \frac{3 \times 3}{10 \times 3}$

$= \frac{35}{30} - \frac{9}{30}$

$= \frac{26}{30}$

$= \frac{13}{15}$

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3 years ago

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Vera_Pavlovna [14]

Answer:

Question #1

m∠4 + m∠7 = 180° - Given.

∠4 and ∠7 are supplementary angles - Definition of supplementary angles.

∠7 and ∠2 form a linear pair - Definition of linear pair.

∠7 and ∠2 are supplementary angles - Definition of linear pair.

m∠7 + m∠2 = 180° - Definition of supplementary angles.

m∠2 = m∠4 - Substitution property.

c ║ d - Converse of corresponding angles postulate.

Question #2

m∠3 = m∠8 - Given.

∠8 and ∠6 form a linear pair - Definition of linear pair.

∠8 and ∠6 are supplementary angles - Definition of linear pair.

m∠8 + m∠6 = 180° - Definition of supplementary angles.

∠3 and ∠6 are supplementary angles - Substitution property.

m∠3 + m∠6 = 180° - Definition of supplementary angles.

Question #3

p ║ q - Given.

∠1 ≅ ∠5 - Given.

∠1 ≅ ∠2 - Alternate interior angle theorem.

∠2 ≅ ∠5 - Substitution property.

~Hope this helps!~

5 0

3 years ago