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Serjik [45]
3 years ago
8

Line b passes through points (9, 1) and (1, 6). Line c passes through points (10, 7) and (2, 12). Are line b and line c parallel

or perpendicular?
Mathematics
1 answer:
andre [41]3 years ago
8 0
<h2>Answer:  Lines b & c are parallel.⇄</h2>

Step-by-step explanation:

  • When lines are perpendicular, the product of their slope is -1 (the slopes are negative reciprocal).
  • When lines are parallel, they have the same slope.

Slope = ( y₂ - y₁) / (x₂ - x₁)

Slope of Line b = ( 6 - 1 ) ÷ ( 1 - 9 )

                         =  5  ÷  (- 8)

                         =   - ⁵/₈

Slope of Line c =  ( 12 - 7 )  ÷  ( 2 - 10 )

                         =  - ⁵/₈

⇒ Line b ║ Line c

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Based on the question
nlexa [21]

From the given table, we have that the lateral limits of f(x) as x -> 3 are different, hence the limit of f(x) does not exist at x = 3.

<h3>What is a limit?</h3>

A limit is given by the value of function f(x) as x tends to a value. For the limit to exist, the lateral limits have to be the same, as follows:

\lim_{x \rightarrow a^-} f(x) = \lim_{x \rightarrow a^+} f(x)

In this problem, we have that:

  • To the left of x = 3, that is, for values that are less than x = 3, f(x) - > -3.
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Hence the lateral limits are given as follows:

  • \lim_{x \rightarrow 3^-} f(x) = -3
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Since the lateral limits are different, the limit does not exist.

More can be learned about lateral limits at brainly.com/question/26270080

#SPJ1

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