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padilas [110]
2 years ago
12

The price of 14 bowls, 9 pans and 12 dishes is $135;

Mathematics
1 answer:
Marysya12 [62]2 years ago
4 0

Answer:

$94

Step-by-step explanation:

Let the price of a bowl, a pan and a dish be $b, $p and $d respectively.

14b +9p +12d= 135 -----(1)

10b +6p +8d= 88 -----(2)

Subtracting equation (1) with equation (2):

14b +9p +12d -(10b +6p +8d)= 135 -88

Expand:

14b +9p +12d -10b -6p -8d= 47

4b +3p +4d= 47

Multiply both sides by 2:

8b +6p +8d= 47(2)

8b +6p +8d= 94

Thus, the price of 8 bowls, 6 pans and 8 dishes is $94.

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I have $25 all in nickels and dimes. There are twice as many Nickles as dimes. How many of each are there?
Mama L [17]

Answer:

N=250

Step-by-step explanation:

 "twice as many nickels as dimes"     means    N =2D     [eq1]

 "collection of nickels and dimes is worth $25"    means

        5N + 10D = 2500      [eq2]

   (To avoid using decimal points, PLZ express everything in cents.)

Substitution   (substitute N from eq1 into eq2]:

     5(2D) + 10D = 2500

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Check:

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7 0
3 years ago
W(1,8),X(7,8),Y(4,5), and Z(1,2) select all methods you can use to prove WYZ is congruent to WYX
marin [14]
The distance between two points (x₁,y1),(x₂,y₂) is d
d= \sqrt{(x2-x1)^2 + (y2-y1)^2}

For the given problem we have
<span>W(1,8),X(7,8),Y(4,5), and Z(1,2)

The length of WY = </span>\sqrt{(4-1)^2 + (5-8)^2} = 3√2
The length of WX = \sqrt{(7-1)^2 + (8-8)^2} = 6
The length of WZ = \sqrt{(1-1)^2 + (2-8)^2} = 6
The length of XY = <span><span>\sqrt{(4-7)^2 + (5-8)^2} = 3√2
</span>The length of ZY = </span><span>\sqrt{(1-4)^2 + (2-5)^2} = 3√2

∴ WX = WZ  ⇒⇒⇒ proved
    XY = ZY   ⇒⇒⇒ proved
    WY = WY  ⇒⇒⇒ reflexive property

∴ Δ</span><span>WYZ is congruent to ΔWYX by SSS method</span>





5 0
3 years ago
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