Question

The price of 14 bowls, 9 pans and 12 dishes is $135;

Answer 1

Answer:

$94

Step-by-step explanation:

Let the price of a bowl, a pan and a dish be $b, $p and $d respectively.

14b +9p +12d= 135 -----(1)

10b +6p +8d= 88 -----(2)

Subtracting equation (1) with equation (2):

14b +9p +12d -(10b +6p +8d)= 135 -88

Expand:

14b +9p +12d -10b -6p -8d= 47

4b +3p +4d= 47

Multiply both sides by 2:

8b +6p +8d= 47(2)

8b +6p +8d= 94

Thus, the price of 8 bowls, 6 pans and 8 dishes is $94.