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Airida [17]
4 years ago
6

When you walk at an average speed (constant speed, no acceleration) of 20.7 m/s in 75.8 sec you will cover a distance of______?

Physics
1 answer:
insens350 [35]4 years ago
7 0

Answer:

You will cover a distance of 1569.06 metres. Or you could round down to 1,569m.

Explanation:

20.7*75.8=1563.06

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Which of these is a cultural service—a non material benefit people get from the environment
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The answer is Providing national parks
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You buy a light bulb in the U.S. labeled 75 watts. Since you bought it in the U.S., the power rating assumes that the potential
MrRissso [65]

Answer:

    P₂ = 252 W

Explanation:

The electrical power is

          P = V I

The potential difference is

         V = I R

         I = V / R

Let's replace

        P = V² / R

Let's use the given values ​​to calculate the resistance of the bulb

         R = V² / P

         R = 120²/75

         R = 192 ohm

This resistance value does not depend on the applied voltage, so it is constant

       

Let's calculate the power in Europe

        P₂ = V₂² / R

       P₂ = 220²/192

       P₂ = 252 W

the bulb dissipates much more power

5 0
3 years ago
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What is the area of the circle with a radius of 12.77m
Arada [10]
A=pi r^2
A=( 3.14159.......)(12.77)^2
A= 512.30m^2
8 0
4 years ago
When is the magnitude of the acceleration of a mass on a spring at its maximum value?
DiKsa [7]

Answer:

D

Explanation:

Now we know that Force is the rate of change of momentum meaning

F= mv/t

But

mv/t = Ke

v/t = ke/m

a= ke/m

Where a is acceleration

K is constant of proportionality of tension on a spring

e is the extension substended by a string.

From the formula of acceleration we can see that as mass decreases acceleration increases so we can see that m = 1

We would have a maximum value of acceleration.

6 0
3 years ago
A 19.0-kg cart is moving with a velocity of 7.20 m/s down a level hallway. A constant force of -13.0 N acts on the cart and its
gulaghasi [49]

Answer:

a. -369.36J

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c. 9.52m

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K. E=1/2mv^2

Since the mass is constant, but the velocity changes. Hence the change in kinetic energy is

K.E=1/2*19(3.6²-7.2²)

K.E= -369.36J

b. to determine the workdone by the force,we determine the distance moved.

But the acceleration is from

F=ma ,

a=f/m

a=-13/19

0.68m/s²

the distance moved is

s=v²/2a

s=3.6²/2*0.68

s=9.52m

Hence the work done is

W=force * distance

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s=3.6²/2*0.68

s=9.52m

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