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3 years ago

A(n)_______is a reflected sound wave.

Physics

1 answer:

strojnjashka [21]3 years ago

3 0

Answer:

A reflected sound wave can be one of two things, an echo or a reverberation. Reverberation happens when sound bounces off surfaces and reaches back to the ear within 0.1 seconds. Echoes happen when sound waves bounce back to the ear after more than 0.1 seconds.

Explanation:

hehe

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Which of the following statements are true? Check all that apply. A.Earth's geographic south pole is also a magnetic south pole.

ycow [4]

Answer:

C.The north pole of a bar magnet will attract the south pole of another bar magnet.

D.The south poles of two bar magnets will repel each other.

F.Earth's geographic north pole is actually a magnetic south pole.

Explanation:

The magnetic field is a region of space that exerts a force on charged particles in motion or on magnets.

A magnet is an object that produces a magnetic field in the region around it - a magnet always consists of a north pole and of a south pole; it is not possible to create a magnetic monopole: if a magnet is cut in a half, we end up with two new magnets, each of them having its own north and south pole.

The lines showing the direction of the magnetic field always go from the north pole towards the south pole.

When a magnet is placed near another magnet, the two magnets can attract/repel each other. In particular:

- Same poles (north-north and south-south) repel each other

- Opposite poles (north-south) attract each other

Moreover, the Earth has also a magnetic field, and its axis acts as a huge magnet. The location of the magnetic North pole corresponds to the location of the geographic South pole, and vice-versa.

According to what we said so far, the correct statements are:

C.The north pole of a bar magnet will attract the south pole of another bar magnet.

D.The south poles of two bar magnets will repel each other.

F.Earth's geographic north pole is actually a magnetic south pole.

4 0

4 years ago

A .5kg football is thrown with a velocity of 15m/s to the right. A stationary receiver catch the bail and bring it to rest in 0.

storchak [24]

<h3>Answer:</h3>

375 N

<h3>Explanation:</h3>

Topic tested: Newton's Law of motion

The question is testing on the application of Newton's second Law of motion.

We are given;

Mass of the football = 5 Kg
Initial velocity of the football, Vf = 15 m/s
Time taken to bring the ball to rest = 0.2 s
Final velocity, Vo = 0 m/s ( since the ball went to rest)

We are required to determine the force exerted to bring it to rest.

According to the Newton's second law of motion the resultant force and rate of change in momentum are directly proportion.

Therefore;

$F=\frac{(MVf-MVo)}{t}$

Thus;

$F=\frac{(5kg.5m/s)-(5kg.0m/s)}{0.2s}$

$F=375Newtons$

Force = 375 N

Hence, the force exerted on the ball by the receiver was 375 N

5 0

4 years ago

You are designing a 108 cm3 right circular cylindrical can whose manufacture will take waste into account. There is no waste in

FinnZ [79.3K]

Explanation:

It is given that,

The volume of a right circular cylindrical, $V=108\ cm^3$

We know that the volume of the cylinder is given by :

$V=\pi r^2 h$

$108=\pi r^2 h$

$h=\dfrac{108}{\pi r^2}$ ............(1)

The upper area is given by :

$A=32r^2+2\pi rh$

$A=32r^2+2\pi r\times \dfrac{108}{\pi r^2}$

$A=32r^2+\dfrac{216}{r}$

For maximum area, differentiate above equation wrt r such that, we get :

$\dfrac{dA}{dr}=64r-\dfrac{216}{r^2}$

$64r-\dfrac{216}{r^2}=0$

$r^3=\dfrac{216}{64}$

r = 1.83 m

Dividing equation (1) with r such that,

$\dfrac{h}{r}=\dfrac{108}{\pi r}$

$\dfrac{h}{r}=\dfrac{108}{\pi 1.83}$

$\dfrac{h}{r}=59 \pi$

Hence, this is the required solution.

8 0

3 years ago

A gnat takes off from one end of a pencil and flies around erratically for 41.641.6 s before landing on the other end of the sam

wlad13 [49]

Answer:

average speed is 0.159 m/s

average velocity = 0.0011 m/s

Explanation:

given data

time = 41.6 s

total distance = 6.65 m

length = 0.0463 m

to find out

average speed and the magnitude average velocity

solution

we know average speed formula is

average speed = $\frac{total distance}{total time}$ ...............1

put here value

average speed = $\frac{6.65}{41.6}$

average speed is 0.159 m/s

and

average velocity formula is

average velocity = $\frac{displacement}{total time}$ ...............2

here displacement is initial point to final point and here is 0.0463 m

put here value

average velocity = $\frac{0.0463}{41.6}$

average velocity = 0.0011 m/s

6 0

4 years ago

Five identical springs, each with stiffness 420 N/m, are connected in parallel (that is, side by side) to hold up a heavy weight

balu736 [363]

Answer:

Not surr

Explanation:

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7 0

4 years ago