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11Alexandr11 [23.1K]
3 years ago
5

Why must one leg of a triangle that the Pythagorean triple represents need an even-numbered length?

Mathematics
1 answer:
pashok25 [27]3 years ago
6 0

Most of the square numbers are even.so if we need to find root over we need an even number to convert it to perfect square.

See the example below

  • P=3
  • B=4
  • H=5

\\ \ast\bull\rm\longmapsto H^2=P^2+B^2

\\ \ast\bull\rm\longmapsto H^2=3^2+4^2

\\ \ast\bull\rm\longmapsto H^2=9+16

\\ \ast\bull\rm\longmapsto H^2=25

\\ \ast\bull\rm\longmapsto H=\sqrt{25}

\\ \ast\bull\rm\longmapsto H=5

Some other triplets are

  • (6,8,10)
  • (5,12,13)
  • (8,15,17)
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How to solve 4x^4-6x^3+7/-4x^4
podryga [215]

Answer:

9x^4/4 - 6x^3

Step-by-step explanation:

Group like terms

Add similar elements

Factor out common terms

Multiply.

**Detailed steps are in the picture attached**

-

I hope this helped!

Brainliest is always appreciated :)

7 0
3 years ago
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What is 8÷1/5,multiply 8 by?​
Anit [1.1K]

Answer:

Multiply the 8 by 5

Step-by-step explanation:

8÷1/5

Copy dot flip

8 * 5/1

40

8 0
3 years ago
Let's see who can do this!
aliina [53]

Answer:

28

Step-by-step explanation:

KARLEE HAS 4 PENCIL PACKS.

<h3>1 PENCIL = 1/7 of pack.</h3>

∴ 1 pack has 1/7 multiplied by X.

X/7 = 1, so X is 7.

AND THEREFORE 4 PACKS CONTAIN 7*4 = 28

6 0
3 years ago
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(sqrt3-sqrt3i)^4
Ludmilka [50]

The increasing order of the complex numbers is (√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ =  (-1 + √3i)¹² < (√3 - √3i)⁴.

<h3>Absolute values of the complex numbers</h3>

The absolute values of the complex numbers are determined as follows;

(sqrt3-sqrt3i)^4 = (√3 - √3i)⁴

|z| = \sqrt{(\sqrt{3} )^2 + (\sqrt{3 }\times1 )^2} } \\\\|z| = \sqrt{6}

(-1+sqrt3i)^12 = (-1 + √3i)¹²

|z| = \sqrt{(-1)^2 + (\sqrt{3)^2} } \\\\|z| = \sqrt{4} \\\\|z| = 2

(sqrt 3-i)^6 = (√3 - i)⁶

|z| = \sqrt{(\sqrt{3})^2 + (-1)^2 } \\\\|z| = \sqrt{4} \\\\|z| = 2

(sqrt2-sqrt2i)^8 = (√2 - √2i)⁸

|z| = \sqrt{(\sqrt{2} )^2 + (\sqrt{2})^2 } \\\\|z| = 2

(sqrt2-i)^6 = (√2 - i)⁶

|z| = \sqrt{(\sqrt{2})^2 + (-1)^2} } \\\\|z| = \sqrt{3}

Increasing order of the complex numbers;

(√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ =  (-1 + √3i)¹² < (√3 - √3i)⁴.

Learn more about complex numbers here: brainly.com/question/10662770

#SPJ1

3 0
2 years ago
Two equivalent ratios for 12/60
Marat540 [252]
If you would like to know two equivalent ratios for 12/60, you can calculate this using the following steps:

12/60 = 12/2 / 60/2 = 6/30
6/30 = 6/2 / 30/2 = 3/15
3/15 = 3/3 / 15/3 = 1/5

The result would be 6/30 or 3/15 or 1/5.
8 0
3 years ago
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