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Zarrin [17]
4 years ago
7

Objects in motion eventually stop moving due to a _____ .can someone help me with this question

Physics
1 answer:
Tom [10]4 years ago
8 0

External force.

Air resistance, friction, grass rubbing on a rolling ball, etc.

If there is no external force on a moving object, it keeps going.

Forever !

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Refrigerators are usually kept at about 5∘C, while room temperature is about 20∘C. If you were to take an "empty" sealed 2-liter
expeople1 [14]

Answer:

The volume will not contract to one fourth of the original.

Explanation:

Applying Charles's Law as:

\frac {V_1}{T_1}=\frac {V_2}{T_2}

Given ,  

V₁ = ?

V₂ = 2 L

T₁ = 5 °C

T₂ = 20 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,

T₁ = (5 + 273.15) K = 278.15 K  

T₂ = (20 + 273.15) K = 293.15 K  

Using Charles law as:

V_1=\frac {V_2}{T_2} \times {T_1}

V_1=\frac {2\ L}{293.15 K} \times {278.15 K}

V_1=1.8977 L

Thus, the volume will not contract to one fourth of the original. (1/4 of 2 L is 0.5 L).

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3 years ago
Am radio signals have frequencies between 550 khz and 1600 khz (kilohertz) and travel with a speed of 3.00 ✕ 108 m/s. what are t
Allisa [31]
The minimum frequency is 
f_1 = 550 kHz = 5.50 \cdot 10^5 Hz
while the maximum frequency is
f_2 = 1600 kHz = 1.6 \cdot 10^6 Hz
Using the relationship between frequency f of a wave, wavelength \lambda and the speed of the wave v, we can find what wavelength these frequencies correspond to:
\lambda_1 =  \frac{v}{f_1}= \frac{3 \cdot 10^8 m/s}{5.5 \cdot 10^5 Hz}=545 m
\lambda_2 =  \frac{v}{f_2}= \frac{3 \cdot 10^8 m/s}{1.6 \cdot 10^6 Hz}=188 m

So, the wavelengths of the radio waves of the problem are within the range 188-545 m.

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