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gtnhenbr [62]
3 years ago
14

Why must there be a chain at the bottom of a truck​

Physics
1 answer:
MrRa [10]3 years ago
7 0

Answer:

Known as automatic tire chains and sometimes referred to by brand names like Onspot or Insta-Chain, these chains essentially hang listlessly from the vehicle's suspension until inclement weather arrives. When that happens, a driver can flip a switch that will lower the chains so they hang in front of the back tires.

Explanation:

(Happy to Help)

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The free-body diagram below represents the force of several vehicles driving across a bridge. Assume that the bridge is in stati
krek1111 [17]

In order to calculate the unknown reaction force, we need to know that the sum of forces pointing down is equal the sum of the forces pointing up, so all forces will be in equilibrium.

So we have:

\begin{gathered} 17800+150000+13200=121000+x \\ 181000=121000+x \\ x=181000-121000 \\ x=60000 \end{gathered}

7 0
1 year ago
1.
Jet001 [13]

Answer:

1. high frequency and high energy.

2. short wavelengths and high frequencies.

3. less energy and long wavelengths.

4. high frequencies and high energy

5. X-rays

6. infrared waves

7. radio waves.

8. Gamma Rays

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4 0
3 years ago
Read 2 more answers
A tank having a volume of 0.85 m 3 initially contains water as a two-phase liquid-vapor mixture at 260 o C and a quality of 0.7.
Keith_Richards [23]

Answer:=14,160 kJ

Explanation: Let m1 and m2 be the initial and final amounts of mass within the tank, respectively. The steam properties are listed in the table below

Specific Internal SpecificTemp Pressure Volume Energy Enthalpy Quality Phase

C MPa m^3/kg kJ/kg kJ/kg

1 260 4.689 0.02993 2158 2298 0.7 Liquid Vapor Mixture

2 260 4.689 0.0422 2599 2797 1 Saturated Vapor

The mass initially contained in the tank is m1 = V/v1

m1 =0.85 m^3 /0.02993 m^3 /kg

= 28.4 kg

The mass finally contained in the tank is

m2 =V2/v

= 0.85 m^3 /0.0422 m^3 /kg

= 20.14 kg

The heat transfer is then

Qcv = m2u2 − m1u1 − he(m2 − m1)

Qcv = (20.14)(2599) − (28.4)(2158) − (2797)(20.14 − 28.4) = 14,160 kJ

4 0
3 years ago
How would you eliminate the unit in this conversion? 5 mil to m
m_a_m_a [10]

Answer:

https://youtu.be/9iulv2QvKwo

3 0
3 years ago
Does the vertical or horizontal position affect an objects potential energy?
son4ous [18]
Yes. If an object would be vertical, it would most likely have potential energy due to gravity. 
6 0
3 years ago
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