Answer:
M_c = 100.8 Nm
Explanation:
Given:
F_a = 2.5 KN
Find:
Determine the moment of this force about C for the two cases shown.
Solution:
- Draw horizontal and vertical vectors at point A.
- Take moments about point C as follows:
M_c = F_a*( 42 / 150 ) *144
M_c = 2.5*( 42 / 150 ) *144
M_c = 100.8 Nm
- We see that the vertical component of force at point A passes through C.
Hence, its moment about C is zero.
In quantum mechanics, a central concept is that both matter and <u>energy</u> are alternate forms of the same entity and therefore both exhibit dual characteristics of particles and of <u>waves</u>.
Matter can be defined as anything that has mass and is able to occupy space.
Thus, any physical object or substance that is found on Earth is typically composed of matter.
Similarly, energy is highly affected by the mass of a any physical object or substance just like matter,
Hence, both energy and matter are known to be made up of atoms and as a result of this fact, exhibit dual characteristics of particles and of waves.
A wave can be defined as a disturbance in a medium that progressively transports energy from a source location to another location without the transportation of matter.
In conclusion, this central concept makes it easier for us to better understand the behavior of tiny particles such as electrons.
Find more information: brainly.com/question/17203857
Answer:
38.4 m/s
Explanation:
a) at t = 3.2s. 
b) at t = 3.2 + Δt. 
c) As Δt approaches 0. We can find the velocity by the ratio of Δx/Δt
As Δt approaches 0, v = 38.4 + 0 = 38.4 m/s
Explanation:
Use Pythagorean theorem:
r² = x² + y²
r² = (-6.46 m)² + (-3.78 m)²
r = 7.48 m
