The displacement volume in liters is 2.74 liters.
<h3>What is displacement volume?</h3>
Displacement volume is the quantity of solvent that will be displaced by a specified quantity of a solid during dissolution.
It can also be defined as the volume displaced by the piston as it moves between top dead center and bottom dead center in a car engine.
<h3>Displacement volume in liters</h3>
1 liter = 61.02 in³
? = 167 in³
= 167/61.02
= 2.74 liters
Thus, the displacement volume in liters is 2.74 liters.
Learn more about displacement volume here: brainly.com/question/1945909
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Answer:
40 km/h
Explanation:
First...
Look at the formula speed is equal to the distance over time or s = d/t.
Next...
Use the formula: 240/6.0
Finally...
Solve: 40
So the answer: 40 km/h
Answer:
Psm = 30.66 [Psig]
Explanation:
To solve this problem we will use the ideal gas equation, recall that the ideal gas state equation is always worked with absolute values.
P * v = R * T
where:
P = pressure [Pa]
v = specific volume [m^3/kg]
R = gas constant for air = 0.287 [kJ/kg*K]
T = temperature [K]
<u>For the initial state</u>
<u />
P1 = 24 [Psi] + 14.7 = 165.47[kPa] + 101.325 = 266.8 [kPa] (absolute pressure)
T1 = -2.6 [°C] = - 2.6 + 273 = 270.4 [K] (absolute Temperature)
Therefore we can calculate the specific volume:
v1 = R*T1 / P1
v1 = (0.287 * 270.4) / 266.8
v1 = 0.29 [m^3/kg]
As there are no leaks, the mass and volume are conserved, so the volume in the initial state is equal to the volume in the final state.
V2 = 0.29 [m^3/kg], with this volume and the new temperature, we can calculate the new pressure.
T2 = 43 + 273 = 316 [K]
P2 = R*T2 / V2
P2 = (0.287 * 316) / 0.29
P2 = 312.73 [kPa]
Now calculating the manometric pressure
Psm = 312.73 -101.325 = 211.4 [kPa]
And converting this value to Psig
Psm = 30.66 [Psig]
Answer:
i think the answer is 12 ohms
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Answer:
see below
Explanation:
Gases flying out at high velocity out the back
rocket flying forward