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3 years ago

We see the Sun before it comes above the horizon. Explain.

Physics

1 answer:

siniylev [52]3 years ago

3 0

Answer:

Atmospheric refraction causes the Sun to be seen while it is still below the horizon. Light from the lower edge of the Sun's disk is refracted more than light from the upper edge. This reduces the apparent height of the Sun when it appears just above the horizon.

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A spherical balloon has a radius of 8.35 m and is filled with helium. how large a cargo can it lift, assuming that the skin and

rusak2 [61]

Assuming that the densities of the gases are:

density of air, ρ1 = 1.29 kg / m^3

density of helium, ρ2 = 0.179 kg / m^3

Since buoyant force and weight are two forces that are in opposite direction (buoyant force is up while weight is down), therefore equate the two:

buoyant force = weight

m g = (800 + m1) g

where m is the mass of buoyancy, g is gravity and m1 is the maximum mass of the cargo

m = 800 + m1

We know that mass is also expressed as:

m = ρ V

where ρ is density of gas and V is volume of the sphere

Since there are two interacting gases here, therefore m is:

m = (ρ1 – ρ2) V

Therefore:

(ρ1 – ρ2) V = 800 + m1

(1.29 – 0.179) (4π/3) (8.35m)^3 = 800 + m1

2709.33 = 800 + m1

m1 = 1,909.33 kg

7 0

3 years ago

Which property of the sound wave changes when the volume is increased on a radio?.

ch4aika [34]

Answer:

amplitude

Explanation:

When we increase the volume of a sound, the amplitude of the wave is increased. The frequency of a wave is related to its pitch. If the pitch is high, then the frequency of the wave is high. This means that the wave will looked squashed on an oscilloscope trace.

8 0

2 years ago

In this unit, the amount of solute is measured in?

Hoochie [10]

Try liters if you haven’t done it yet. I’m so sorry if i’m incorrect.

5 0

3 years ago

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The diagram shows waves of sound travelling through the air. By which factor is the sound intensity decreased at 3 meters?

SIZIF [17.4K]

The diagram is missing; however, we know that the intensity of a sound wave is inversely proportional to the square of the distance from the source:
$I(r)= \frac{1}{r^2}$
where I is the intensity and r is the distance from the source.

We can assume for instance that the initial distance from the source is r=1 m, so that we put
$I= \frac{1}{r^2}= \frac{1}{(1)^2}=1$
The intensity at r=3 m will be
$I= \frac{1}{r^2}= \frac{1}{(3)^2}= \frac{1}{9}$
Therefore, the sound intensity has decreased by a factor $1/9$ .

8 0

3 years ago

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What law of motion does this picture represent?

enyata [817]

Which picture are you talking about?

4 0

3 years ago

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We see the Sun before it comes above the horizon. Explain.​

We see the Sun before it comes above the horizon. Explain.