Answer:
C and D
Explanation:
A uniform probability model is a probabilistic model characterized by a uniform probability density function, or uniform distribution.
In common language, a uniform probability distribution means that all possible outcomes in the probability space have the same probability of occurrence.
So:
- A fair toss of coin every possible outcome (H,T) has probability 0.5. It is modeled by by a uniform discrete distribution.
- Randomly selected answer to an MCQ with four options would have probability of success 0.25 for every MCQ. It is modeled by by a uniform discrete distribution.
- Spinning a spinner with sections that are different sizes, each section would have different probabilities proportional to the coverage area on the. It is modeled by a non-uniform discrete distribution
- Pulling a red marble out of a bag with 6 red marbles, 3 green marbles, and 1 yellow marble. Each successive time a red marble is drawn the probability decreases. Hence, non uniform distribution.
- Spinning a spinner on which all sections are the same size. Each section would have similar probabilities proportional to the coverage area on the. It is modeled by a uniform discrete distribution .
Answer:
1. <u>F = ma</u> <em>F = 0.2kg * 20m/s² = 4Kg * m/s² =</em> 4N
2. <u>F = ma</u> <em>F - 18Kg * 3m/s² = 54Kg * m/s² =</em> 54N
3. <u>F = ma</u> <em>F = 0.025Kg * 5m/s² =</em> 0.125N
4. <u>F = ma</u> <em>F = 50Kg * 4m/s² =</em> 200N
5. <u>F = ma</u> <em>F = 70Kg * 4m/s² =</em> 280N
6. <u>F = ma</u> <em>F = 9Kg * 9.8m/s² =</em> 88.2N
Explanation:
Hope this helps ! ^^
Answer:
Sound waves transfer energy by causing successive compressions and rarefactions in the particles of the medium without transporting the medium particles themselves. Sound in solids can also manifest as transverse waves, causing crests and troughs in the propagation medium.
Answer:
The level of the root beer is dropping at a rate of 0.08603 cm/s.
Explanation:
The volume of the cone is :

Where, V is the volume of the cone
r is the radius of the cone
h is the height of the cone
The ratio of the radius and the height remains constant in overall the cone.
Thus, given that, r = d / 2 = 10 / 2 cm = 5 cm
h = 13 cm
r / h = 5 / 13
r = {5 / 13} h


Also differentiating the expression of volume w.r.t. time as:

Given:
= -4 cm³/sec (negative sign to show leaving)
h = 10 cm
So,



<u>The level of the root beer is dropping at a rate of 0.08603 cm/s.</u>
Answer:
work = 1728
Power = 134
Explaination:
by using the formula,
Work(W)= Force(F)×Distance(D)
<h2>
and</h2>
Power(P)= Work(W)/Time taken(T)