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igomit [66]
3 years ago
11

I think I know the answer but I am not sure

Physics
2 answers:
Romashka [77]3 years ago
5 0
The answer is a

Hope this helps!
Diano4ka-milaya [45]3 years ago
5 0
I wanna bang my head if i see a mathematics
You might be interested in
A uniform, solid, 2000.0 kgkg sphere has a radius of 5.00 mm. Find the gravitational force this sphere exerts on a 2.10 kgkg poi
mars1129 [50]

Answer:

0.0110284391534\ N

0.0653784219002\ N

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

m_1 = Mass of sphere = 2000 kg

m_2 = Mass of other sphere = 2.1 kg

r = Distance between spheres

Force of gravity is given by

F=\dfrac{Gm_1m_2}{r^2}\\\Rightarrow F=\dfrac{6.67\times 10^{-11}\times 2000\times 2.1}{(5.04\times 10^{-3})^2}\\\Rightarrow F=0.0110284391534\ N

The gravitational force is 0.0110284391534\ N

F=\dfrac{Gm_1m_2}{r^2}\\\Rightarrow F=\dfrac{6.67\times 10^{-11}\times 2000\times 2.1}{(2.07\times 10^{-3})^2}\\\Rightarrow F=0.0653784219002\ N

The gravitational force is 0.0653784219002\ N

6 0
3 years ago
2. A stone is thrown vertically upward with a speed of 22m/s.
Eduardwww [97]

Answer:

Explanation:

Energy E is conserved:

E=\frac{1}{2}mv^2+mgh

If v₀ = 22m/s, h₀=0m and h₁=25m:

E=\frac{1}{2}mv_0^2=\frac{1}{2}mv_1^2+mgh_1

Solving for v₁:

v_1=\sqrt{v_0^2-2gh_1}

There is no real solution, because the stone never reaches 25m.

7 0
3 years ago
Show all work.
lys-0071 [83]

The new gravitation force at the new location is 40 N

Explanation:

The weight of the astronaut is given by the equation

F=mg (1)

where

m is the mass of the astronaut

g is the acceleration of gravity

The acceleration of gravity at a certain distance r from the centre of the Earth is given by

g=\frac{GM}{r^2}

where G is the gravitational constant and M is the Earth's mass. So we can rewrite eq.(1) as

F=\frac{GMm}{r^2}

When the astronaut is on the Earth's surface, r=R (where R is the Earth's radius), so his weight is

F=\frac{GMm}{R^2}=640 N

Later, he moves to another location where his distance from the Earth's surface is 3 times the previous distance, so the new distance from the Earth's centre is

r'=3R+R=4R

Therefore, the new weight is

F'=\frac{GMm}{(4R)^2}=\frac{1}{16}\frac{GMm}{R^2}=\frac{F}{16}

Which means that his weight has decreased by a factor 16: therefore, the new weight is

F'=\frac{640}{16}=40 N

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

3 0
3 years ago
Why it is important to have exact standards of measurement
Tamiku [17]

Answer:

reference against doubt

Explanation:

exact standards of measurement are a reference point for situations in doubt , a line against which to test and observe.

6 0
3 years ago
A farmhand attaches a 25-kg bale of hay to one end of a rope passing over a
Georgia [21]

Explanation:

Newton's second law:

∑F = ma

277 N − 245 N = (25 kg) a

a = 1.28 m/s²

8 0
3 years ago
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