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igomit [66]
3 years ago
11

I think I know the answer but I am not sure

Physics
2 answers:
Romashka [77]3 years ago
5 0
The answer is a

Hope this helps!
Diano4ka-milaya [45]3 years ago
5 0
I wanna bang my head if i see a mathematics
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Does 3.60 x 10 ⁻² have 2 significant figures
Mandarinka [93]

Answer:

Number of Significant Figures: 2

The Significant Figures are 3 6

Explanation:

= 3.60 × 102

(scientific notation)

= 3.60e2

(scientific e notation)

= 360 × 100

(engineering notation)

(one)

= 360

(real number)

4 0
2 years ago
Which of the following phenomena support the idea that light is a wave?
Pie

Answer:

Wave theory of light explains the phenomena of interference, diffraction, scattering, dispersion, polarisation etc. Complete solution: Around 1700, it was concluded by Newton that light was a group of particles. It was called corpuscular theory.

3 0
2 years ago
Where is the energy in a glucose molecule stored?
Semmy [17]

Answer:

Energy is stored in the bonds between atoms

4 0
2 years ago
Consider a system to be two train cars traveling toward each other. What is the total momentum of the system before the train ca
Brut [27]

Let say the two train cars are of masses m_1 and m_2

now if the speed of two cars are v_1 and v_2

then we can say that the momentum of two cars before they collide is given by

P = m_1v_1 - m_2v_2

here two cars are moving in opposite direction so we can say that the net momentum is subtraction of two cars momentum.

Now since in these two car motion there is no external force on them while they collide

So the momentum of two cars are always conserved.

hence we can say that the final momentum of two cars will be same after collision as it is before collision

P = m_1v_1 - m_2v_2

5 0
3 years ago
Read 2 more answers
An engine is used to lift a beam weighing 9,800 N up to 145 m. How much work must the engine do to lift this beam? How much work
Arturiano [62]

Explanation:

Given that,

Weight of the engine used to lift a beam, W = 9800 N

Distance, d = 145 m

Work done by the engine to lift the beam is given by :

W = F d

W=9800\ N\times 145\ m\\\\W=1421000\ J\\\\W=1421\ kJ

Let W' is the work must be done to lift it 290 m. It is given by :

W'=9800\ N\times 290\ m\\\\W'=2842000\ J\\\\W'=2842\ kJ

Hence, this is the required solution.

5 0
3 years ago
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