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igomit [66]
3 years ago
11

I think I know the answer but I am not sure

Physics
2 answers:
Romashka [77]3 years ago
5 0
The answer is a

Hope this helps!
Diano4ka-milaya [45]3 years ago
5 0
I wanna bang my head if i see a mathematics
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Derive an expression for the energy needed to launch an object from the surface of Earth to a height h above the surface.Ignorin
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Answer:

Explanation:

Potential energy on the surface of the earth

= - GMm/ R

Potential at height h

=  - GMm/ (R+h)

Potential difference

= GMm/ R -  GMm/ (R+h)

= GMm ( 1/R - 1/ R+h )

= GMmh / R (R +h)

This will be the energy needed  to launch an object from the surface of Earth to a height h above the surface.

Extra  energy is needed to get the same object into orbit at height h

= Kinetic energy of the orbiting object at height h

= 1/2 x potential energy at height h

= 1/2 x GMm / ( R + h)

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3 years ago
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a. Independent variable:   <em>TIME </em>

b. Dependent variable:   <em>DISTANCE</em>

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3 years ago
A 2190 kg car moving east at 10.5 m/s collides with a 3220 kg car moving east. The cars stick together and move east as a unit a
Bezzdna [24]

To solve this problem it is necessary to apply the concepts related to the conservation of the Momentum describing the inelastic collision of two bodies. By definition the collision between the two bodies is given as:

m_1v_1+m_2v_2 = (m_1+m_2)V_f

Where,

m_{1,2}= Mass of each object

v_{1,2}= Initial Velocity of Each object

V_f= Final Velocity

Our values are given as

m_1 = 2190Kg

v_1 =10.5m/s

m_2 = 3220kg

V_f = 4.74m/s

Replacing we have that

m_1v_1+m_2v_2 = (m_1+m_2)V_f

(2190)(10.5)+(3220)v_2 = (2190+3220)(4.74)

v_2 = 0.8224m/s

Therefore the the velocity of the 3220 kg car before the collision was 0.8224m/s

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3 years ago
how will resistance change when the voltage increases in an electric circuit if the current remains constant
Yakvenalex [24]
V=IR
Potential Difference (v)= Current (A) * Resistance (Ω)
As V increases, R also increases.
3 0
3 years ago
Can anyone fill in the blanks for the potential and kentic energy? Also, is this showing energy transformation? Thank you so muc
Bezzdna [24]

Potential Kinetic Kinetic Potential Potential


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3 years ago
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