The definition for nebula is : A cloud of gas and dust in outer space, visible in the night sky either as an indistinct bright patch or as a dark silhouette against other luminous matter.
Answer:
78840
Explanation:
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Answer:
1.31022×10⁻³⁴ kg
Explanation:
Difference in energies = 1189.4-1115.7 MeV = 73.7 MeV
Convert this energy to Joules
1 MeV = 1.6×10⁻¹⁹ J
73.7 MeV = 73.7×1.6×10⁻¹⁹ J = 117.92×10⁻¹⁹ J
c = Speed of light = 3×10⁸ m/s
From Einstein's equation
E = mc²
∴ Difference in their masses is 1.31022×10⁻³⁴ kg
Answer:
Acceleration of the bullet while moving into the clay is -312500 ms⁻²
Explanation:
Given data
Initial velocity (v₁) = 250 m/s Final velocity (v₂) = 0 m/s
Distance (s)= 0.1 m acceleration (a) = ?
Using 3rd equation of motion
2as = v₂²- v₁²
2 × a × 0.1 = 0² - 250²
0.2 × a = -62500
a = -62500/0.2
a = -312500 m/s²
Here negative sign indicate that bullet slow down and it is deceleration i.e negative acceleration.
Answer:
v = 1.98*10^8 m/s
Explanation:
Given:
- Rod at rest in S' frame
- makes an angle Q = sin^-1 (3/5) in reference frame S'
- makes an angle of 45 degree in frame S
Find:
What must be the value of v if as measured in S the rod is at a 45 degree)
Solution:
- In reference frame S'
x' component = L*cos(Q)
y' component = L*sin(Q)
- Apply length contraction to convert projected S' frame lengths to S frame:
x component = L*cos(Q) / γ (Length contraction)
y component = L*sin(Q) (No motion)
- If the rod is at angle 45° to the x axis, as measured in F, then the x and y components must be equal:
L*sin(Q) = L*cos(Q) / γ
Given: γ = c / sqrt(c^2 - v^2)
c / sqrt(c^2 - v^2) = cot(Q)
1 - (v/c)^2 = tan(Q)
v = c*sqrt( 1 - tan^2 (Q))
For the case when Q = sin^-1 (3/5)::
tan(Q) = 3/4
v = c*sqrt( 1 - (3/4)^2)
v = c*sqrt(7) / 4 = 1.98*10^8 m/s
