1. We will use the Cosine Law:
x² = 60² + 28² - 2 · 60 · 28 · cos 50°
x² = 3,600 + 784 - 3360 · 0.6428
x² = 2,224.234
x = √2,224.234
x = 47.16 pounds ≈ 47.2
Answer: B ) 47.2 pounds
2. By the Cosine Law ( angle of 135° is opposite the forces resultant ):
R² = 150² + 50² - 2 · 150 · 50 · cos 135°
R² = 22,500+2,500 -15,000 · ( -0.71 )
R² = 35,650
R = √35,650 = 188.812 mph
After that we will use the Sine Law:
50 / sin α = 188.812 / sin 135°
50 / sin α = 188.812 / 0.71
sin α = 50 · 0.71 / 188.812
sin α = 0.188
α = sin^(-1) 0.188
α = 10.83° ≈ 10.8°
Answer: C ) 10.8°
Answer:
w = 28.4 yds
Step-by-step explanation:
P = 12.7 + 4 + 2w
73.5 = 16.7 + 2w
56.8 = 2w
w = 56.8/2
w = 28.4
Answer:
your answer will be x=1.13504161
Answer:
4.28
I think this it. I used a calculator online to help solve this problem. I don't know what the answer is but I used an online calculator to solve the problem. I rounded the answer to the nearest hundreth.
Answer:
h(8q²-2q) = 56q² -10q
k(2q²+3q) = 16q² +31q
Step-by-step explanation:
1. Replace x in the function definition with the function's argument, then simplify.
h(x) = 7x +4q
h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q
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2. Same as the first problem.
k(x) = 8x +7q
k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q
_____
Comment on the problem
In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...
h(8q² -2q) = 56q² -14q +4z
and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.
In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.
