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Nostrana [21]
3 years ago
14

Smog is a mixture of smoke, fog and which other substance?

Chemistry
2 answers:
Anit [1.1K]3 years ago
5 0
I believe the answer is exhaust fumes, but there are other things it that it could be.
larisa [96]3 years ago
3 0
Smog = smoke and fog only
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A student is given two 10g samples, each a mixture of only NaCl(s) and KCl(s) but in different proportions. Which of the followi
8090 [49]

Answer:

The information that can be used to determine which mixture has the higher proportion of KCl IS INFORMATION ABOUT THE MASS OF CHLORINE IN EACH MIXTURE, THIS INFORMATION CAN BE OBTAINED BY USING THE LAW OF DEFINITE PROPORTION.

Explanation:

The law of definite proportion states that the chemical composition by mass of a chemical compound is always constant. For instance, a chemical compound that is made up of two elements will always contain the same proportions of the constituent elements regardless of the quantity of chemical that was used.

Using the law of definite proportion, we can determine the proportion of sodium and chlorine in NaCl and the proportion of potassium and chlorine in KCl if the mass of chlorine that was used is known. Based on the results obtained, one can easily determine the mixtures that has higher proportion of KCl.

6 0
3 years ago
Read 2 more answers
Why can scientist assume elastic collisions as long as the temperature remains constant?
Tema [17]

Answer:

Because in elastic collisions there is no heat emission or absorption.

Explanation:

A collision is considered elastic when the total kinetic energy of the study system is conserved during the collision. Since the total kinetic energy is conserved, heat is not emitted or absorbed during the collision. Since the emission or absorption of heat is what produces changes in temperature, If the system remains at a constant temperature, there were only elastic collisions.

8 0
4 years ago
In nature, one common strategy to make thermodynamically unfavorable reactions proceed is to couple them chemically to reactions
padilas [110]

Answer:

\triangle G= -6.7 KJ/mol

Explanation:

From the question we are told that:

Chemical Reactions:

X=A⇌B,ΔG= 14.8 kJ/mol

Y=B⇌C,ΔG= -29.7 kJ/mol

Z=C⇌D,ΔG= 8.10 kJ/mol

Since

Hess Law

The law states that the total enthalpy change during the complete course of a chemical reaction is independent of the number of steps taken.

Therefore

Generally the equation for the Reaction is mathematically given by

T = +1 * X +1 * Y +1 *Z

Therefore the free energy, ΔG is

\triangle G=1 * \triangle G*X +1 * \triangle G*Y +1 * \triangle G *Z

\triangle G= +1 * (14.9) +1 * (-29.7) +1 * (8.10)

\triangle G= -6.7 KJ/mol

5 0
3 years ago
How many individual orbitals does carbon use for all of its electrons? Remember, there are two electrons in each filled orbital
Andreas93 [3]

Answer:

Three orbitals

Explanation:

The electronic configuration of carbon is given as follows;

1s²2s²2p²

Therefore, out of the six electrons of the carbon atoms, 4 fill the 1s and 2s orbitals with 2 electrons each, while the two remaining electrons are situated in the 2p orbital, with the electrons in the 2p orbital will remain unpaired such that they will have similar quantum numbers in accordance with Pauli exclusion principle.

4 0
3 years ago
For the reaction shown, calculate how many grams of oxygen form when each quantity of reactant completely reacts.
Nikolay [14]

Explanation:

Molar mass of KClO_{3} = 39.1 + 35.5 + 3(16.0) = 122.6 g

Molar mass of KCl = 39.1 + 35.5 = 74.6 g

Molar mass of O_{2} = 32.0 g

According to the equation, 2 moles of KClO_{3} reacts to give 3 moles of oxygen.

Therefore, 2 (122.6) = 245.2 g of KClO_{3} will give 3 (32.0) = 96.0 g of oxygen. Thus, 245.2 g of KClO_{3} gives 96.0 g of oxygen.

(a) Calculate the amount of oxygen given by 2.72 g of KClO_{3} as follows.

       \frac {96g}{245.2g} \times 2.72 g = 1.06 g of O_{2}


(b) Calculate the amount of oxygen given by 0.361 g of KClO_{3} as follows.

    \frac {96g}{245.2g} \times 0.361 g = 0.141 g of O_{2}


c) Calculate the amount of oxygen given by 83.6 kg KClO_{3} as follows.  

    \frac {96g}{245.2g} \times 83.6 g = 32.731 kg of O_{2}

Convert kg into grams as follows.

    \frac{32.731 kg}{1 kg} \times 1000 g = 32731 g of O_{2}


(d) Calculate the amount of oxygen given by 22.5 mg of KClO_{3} as follows.  

    \frac {96g}{245.2g} \times 22.5 mg = 8.79 mg

Convert mg into grams as follows.

  \frac{8.79 mg}{1 mg}\times 10^{-3} g = 8.79 \times 10^{-3} g of O_{2}

8 0
3 years ago
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