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Ugo [173]
3 years ago
12

Given that:2NO (g)→N2 (g)+O2 (g)N2 (g)+O2 (g)+Cl2 (g)→2NOCl (g) has an enthalpy change of −180.6 kJ has an enthalpy change of 10

3.4 kJ What is the enthalpy change, in kilojoules, for 2NOCl (g)→2NO (g)+Cl2 (g)?
Chemistry
1 answer:
likoan [24]3 years ago
6 0

Answer:

Explanation:

It is possible to answer this question knowing Hess's law that says you can sum half-reactions enthalpy cahnge to obtain enthalpy change of the total reaction. Using the reactions:

<em>(1) </em>2NO(g) → N₂(g)+O₂(g) ΔH = -180,6 kJ

<em>(2) </em>N₂(g) + O₂(g) + Cl₂(g) → 2NOCl(g) ΔH = +103,4 kJ

The reverse reactions of (1) and (2) are:

<u>N₂(g)+O₂(g)</u> → 2NO(g) ΔH = +180,6 kJ

2NOCl(g) → <u>N₂(g) + O₂(g)</u> + Cl₂(g) ΔH = -103,4 kJ

The sum of these reactions is:

2NOCl(g) → 2NO(g) + Cl₂(g) ΔH = +180,6 kJ -103,4 kJ = <em>77,2 kJ</em>

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I hope it helps!

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