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PtichkaEL [24]
3 years ago
9

What is the volume of liquid in this graduated cylinder? Be sure your answer has a reasonable number of decimal places.

Chemistry
1 answer:
Amiraneli [1.4K]3 years ago
8 0

Answer:

76 ml

Explanation:

The complete question is attached in the image.

The volume of a liquid is the amount of space that the liquid occupies or contains. Since for a liquid, it takes the shape of the container, when measuring the volume, we just measure the space occupied by the liquid in the container.

From the image, when determining the volume, we are to use the value of the lower meniscus. Hence the volume of the liquid is gotten to be 76 ml

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Explain the environmental benefits of recyling paper products.
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Heating carvone with aqueous sulfuric acid converts it into carvacrol. The mechanism involves the following steps:
Fittoniya [83]

Answer:

See figure 1

Explanation:

In this question, we have to start with the <u>protonation of the double bond</u>. In carvone we have two double bonds, so, we have to decide first which one would be protonated.

The problem states that the <u>terminal alkene</u> is the one that would is protonated. Therefore, we have to do the <u>protonation</u> in the double bond at the bottom to produce the <u>carbocation number 1</u>. Then, a hydride shift takes place to produce the <u>carbocation number 2</u>. A continuation, an <u>elimination reaction</u> takes place to produce the <u>conjugated diene</u>. Then the diene is protonated at the <u>carbonyl group</u> and with an elimination reaction of an hydrogen in the <u>alpha carbon</u> we can obtain <u>carvacol. </u>

5 0
3 years ago
A hand-operated conduit bender with a shoe for bending 1-inch EMT can also be used to bend
mixer [17]
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6 0
3 years ago
When a mercury-202 nucleus is bombarded with a neutron, a proton is ejected. What element is formed?
Galina-37 [17]

That will make a gold-202 nucleus.

<h3>Explanation</h3>

Refer to a periodic table. The atomic number of mercury Hg is 80.

Step One: Bombard the \displaystyle ^{202}_{\phantom{2}80}\text{Hg} with a neutron ^{1}_{0}n. The neutron will add 1 to the mass number 202 of ^{202}_{\phantom{2}80}\text{Hg}. However, the atomic number will stay the same.

  • New mass number: 202 + 1 = 203.
  • Atomic number is still 80.

^{202}_{\phantom{2}80}\text{Hg} + ^{1}_{0}n \to ^{203}_{\phantom{2}80}\text{Hg}.

Double check the equation:

  • Sum of mass number on the left-hand side = 202 + 1 = 203 = Sum of mass number on the right-hand side.
  • Sum of atomic number on the left-hand side = 80 = Sum of atomic number on the right-hand side.

Step Two: The ^{203}_{\phantom{2}80}\text{Hg} nucleus loses a proton ^{1}_{1}p. Both the mass number 203 and the atomic number will decrease by 1.

  • New mass number: 203 - 1 = 202.
  • New atomic number: 80 - 1 = 79.

Refer to a periodic table. What's the element with atomic number 79? Gold Au.

^{203}_{\phantom{2}80}\text{Hg} \to ^{202}_{\phantom{2}79}\text{Au} + ^{1}_{1}p.

Double check the equation:

  • Sum of mass number on the left-hand side = 203 = 202 + 1 = Sum of mass number on the right-hand side.
  • Sum of atomic number on the left-hand side = 80 = 79 + 1 = Sum of atomic number on the right-hand side.

A gold-202 nucleus is formed.

6 0
3 years ago
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