Answer:
0 < x ≤ 12 and 0 < y ≤ 36
Step-by-step explanation:
Here, x represents the number of female gazelles and y represents the number of male gazelles.
The zoo only has room for 12 female gazelles.
∵ The number of rooms must be more than or equal to the total female gazelles ,
12 ≥ x
Also, number of animals can not be negative,
And, it must be greater than 0.
⇒ 0 < x ≤ 12,
⇒ 3(0) < 3x ≤ 3(12)
⇒ 0 < 3x ≤ 36
∵ Number of males gazelles = 3 × number of female gazelles
⇒ y = 3x
⇒ 0 < y ≤ 36
Hence, the constraints to represent a thriving population of gazelles at the zoo are,
0 < x ≤ 12,
0 < y ≤ 36
3x = -5y -------------- (1)
6x - 7y = 17 --------- (2)
From (1):
3x = -5y
x = -5/3 y ---------- sub into (2)
6 (-5/3 y) - 7y = 17
-10y - 7y = 17
-17y = 17
y = -1 ------------ Sub into (1)
3x = -5 (-1)
3x = 5
x = 5/3
Ans: x = 5/3, y = -1
The answer to 22 is C) One person caught fewer that 3 fish.
Answer:
88 adult tickets were sold
Step-by-step explanation:
3s + 7a = 1102
(s + a = 250)-3
3s + 7a = 1102
+ -3s - 3a = -750 Add these equations together
4a = 352 Divide both sides by 4
a = 88
Now plug this into the second equation
s + a = 250
s + 88 = 250
- 88 - 88 Subtract 88 from both sides
s = 162
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