13% of $4000 is $520
If the $4000 car loses value at a rate of 13% each year for 3 years
$520 x 3 = $1560
Subtract this amount from $4000
$4000 - $1560 = $2440
<u>Answer: In 3 years, the used car will be worth $2440 in 3 years</u>
Answer
given,
on first stop
number of car = 20 and number of trucks = 18
on second stop
number of car = 18 and number of trucks = 10
we need to calculate which rest stop has higher ratio of car to truck.
Rest Stop 1
ratio= r₁ =
r₁ =
r₁ =
Rest Stop 2
ratio= r₂ =
r₂ =
r₂=
hence, r₂ > r₁
rest stop 2 has more car to truck ratio than rest stop 1
Answer:
an irrational number
Step-by-step explanation:
Since we know a = 3, substitute this into the expression:
2a² = 2 x 3²
3² = 9
So 2a² = 2 x 9
2a² = 18
We know b = 2 and c = 1, so substitute these values into the expression:
3b² - c³ = 3 x 2² - 1³
2² = 4
1³ = 1
So:
3 x 4 - 1
Using the order of operations we multiply first:
3 x 4 = 12
Take off the 1:
Final answer:
3b² - c³ = 11
8 and -7. 8 + (-7) = 1 and 8 times -7 = -56
