The given function is
The general form of the cosine function is
a is the amplitude
2pi/b is the period
c is the phase shift
d is the vertical shift
By comparing the two functions
a = 4
b = pi
c = 0
d = 1
Then its period is
The equation of the midline is
Since the maximum is at the greatest value of cos, which is 1, then
Since the minimum is at the smallest value of cos, which is -1, then
Then substitute them in the equation of the midline
The answers are:
Period = 2
Equation of the midline is y = 1
Maximum = 5
Minimum = -3
f(x) = 5x is linear. Just a straight line with a slope of +5. So if the intervals are both a difference of 1, then the average rate of change will be the same.
f(x2) - f(x1) over x2 - x1. That's the formula for average rate of change.
So for Section A:
f(x) = 5x, (0,1)
[f(1) - f(0)]/(1-0)
= [5(1) - 5(0)]/1
=(5)/1
=5
Do the same for section B and you'll get 5 as well.
I hope this helps you because I have no clue if my answer is right
When a function intersects with the x-axis, it's y value must be 0. That means when the straight line intersects with the axis, it's at the point (4k,0), so plugging those numbers into our original equation yields:
Answer:
Because the base of this expression is not same.
145=10x-8x it’s A I’m pretty sure
