All categories

3 years ago

Diagonals of parallelograms Solve for x

Mathematics

2 answers:

Lunna [17]3 years ago

3 0

Diagonals bisect each other

$\\ \bull\tt\longmapsto 2x+10=3x$

$\\ \bull\tt\longmapsto 3x-2x=10$

$\\ \bull\tt\longmapsto x=10$

Option B

DerKrebs [107]3 years ago

3 0

Answer:

<u>Answer</u><u>:</u><u> </u><u>1</u><u>0</u>

Assuming the parallelogram is general and congruent:

$2x + 10 = 3x \\ 3x - 2x = 10 \\ x = 10$

You might be interested in

The graph below is based on data collected from a sixth grade class.

KiRa [710]

<h2>Answers :</h2>

a) There are <u>5 subjects</u> in Grade six.

b) 5+7+4+4+5 = There are <u>2</u><u>5</u><u> </u><u>students</u><u> </u> in Grade six.

c) My favourite subject is <u>Maths</u>.

d) My classes start at <u>12 noon.</u>

The question can be :

<h3>What is the class schedule, number of students and subjects in Grade 6? </h3>

8 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP!!!!!!

ioda

The answer is 2.54 feet

5 0

4 years ago

Please Help - Point <br> x^3-4x<-5x^2+20<br> Solve in interval notation and list the zeros

Naddika [18.5K]

hi my name is antonette Jane S pascua please help me my question thank you for your answer

4 0

3 years ago

If the statement "If it is cold, then I wear a jacket" is assumed to be true, is its converse, "If I wear a jacket, then it must

Ad libitum [116K]

it is false, there could be other reasons they wear a jacket other than being cold.

8 0

3 years ago

Find the distance between the points (a,-2) and (3a,5)

romanna [79]

To find the distance between two points $A = (A_x, A_y),\ B = (B_x, B_y)$ you may use the formula

$\overline{AB} = \sqrt{(A_x-B_x)^2+(A_y-B_y)^2}$

In your case, the formula becomes

$\overline{AB} = \sqrt{(a-3a)^2+(-2-5)^2} = \sqrt{(-2a)^2+(-7)^2} = \sqrt{4a^2+49}$

7 0

4 years ago