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nirvana33 [79]
3 years ago
5

Diagonals of parallelograms Solve for x

Mathematics
2 answers:
Lunna [17]3 years ago
3 0

Diagonals bisect each other

\\ \bull\tt\longmapsto 2x+10=3x

\\ \bull\tt\longmapsto 3x-2x=10

\\ \bull\tt\longmapsto x=10

Option B

DerKrebs [107]3 years ago
3 0

Answer:

<u>Answer</u><u>:</u><u> </u><u>1</u><u>0</u>

Assuming the parallelogram is general and congruent:

2x + 10 = 3x \\ 3x - 2x = 10 \\ x = 10

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\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill

\bf \begin{cases} h=-4\\ k=2\\ p=\frac{1}{8} \end{cases}\implies 4\left(\frac{1}{8} \right)(y-2)=[x-(-4)]^2\implies \cfrac{1}{2}(y-2)=(x+4)^2 \\\\\\ y-2=2(x+4)^2\implies \blacktriangleright y = 2(x+4)^2+2 \blacktriangleleft

7 0
3 years ago
Urgent please help..
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