How do we calculate the vertex of a quadratic in standard form?
1 answer:
Answer:
y = a + b x + c .
Step-by-step explanation:
Also (How to do it!):
We can find the vertex of a quadratic equation with these steps:
Get the equation in the form y = ax2 + bx + c.
Calculate -b / 2a. This is the x-coordinate of the vertex.
To find the y-coordinate of the vertex, simply plug the value of -b / 2a into the equation for x and solve for y.
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Answer:
<h3>Explanation:
1.) Rewrite √24 = Rewrite √54 =
Divide both terms by the denominator; √6 cancels. 2-3 = -1
2.) Rewrite as ×
The 3's cancel. 10/2 = 5√2 in the numerator.
√5 × √5 = 5 in the denominator. The 5's cancel.
That leaves √2 ≈1.4142
3.) Divide the terms in the numerator by the term in the denominator.
√2's cancel. 10π/2 = 5π 8π/2 = 4π
Subtract and we are left with π = 3.14159
4.) The square roots are reciprocals. They multiply to 1
We are left with π × π = π² ≈ 9.8696
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