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erastova [34]
2 years ago
10

A 70 kg person walks 200 m in 4 seconds. What is their momentum?

Physics
1 answer:
Gemiola [76]2 years ago
8 0

Answer:

z65td8ztu4a7a5857a57a75477282u2hshshsh7e7eyeyw82773888898 idhw

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3 years ago
If the room radius is 4.5 m, and the rotation frequency is 0.8 revolutions per second when the floor drops out, what is the mini
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<span>The force of static friction F equals the coefficient of friction u times the normal force N the object exerts on the surface: F = uN. N is the centripetal force of the wall on the people; N = ma_N, where m is the mass of the people and a_N is the centripetal acceleration. The people will not slip down if F is greater than the force of gravitation: F = uma_N > mg, or u > g/a_N. a_N is the velocity v of the people squared divided by the radius of the room r: a_N = v^2/r. The circumference of the room is 2 pi r = 28.3 m. So v = 28.3 * 0.8 m/sec = 22.6 m/sec. So a_N = 114 m/sec^2. g = 9.81 m/sec^2, so u must be at least 9.81/114 = 0.086.</span>
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2 years ago
Does the work cause a change in kinetic energy or a potential energy?
Alla [95]

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3 years ago
the value of acceleration due to gravity option A is same on equator and poles option B is list on poles option C is list on equ
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Which statement best explains the speed of light waves as they travel from gas to solid?
igomit [66]

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